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1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...+1/(x+2008)(x+2009

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/08/24 00:50:06
1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...+1/(x+2008)(x+2009)
1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...+1/(x+2008)(x+2009)
=[1/(x+1)-1/(x+2)]+[1/(x+2)-1/(x+3)]+[1/(x+3)-1/(x+4)]+...+[1/(x+2008)-1/(x+2009)]
=1/(x+1)-1/(x+2009)