求﹙x²+y²﹚²-4x²y²的值
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
已知非零有理数x,y满足x²-4xy+4y²=0,求x-y/x+y-y-x/x+y的值.
已知x-y=4,x²-y²=20,求x-y的值
已知x² +y²+5/4=2x+y,求y-x的值
已知x²+4y²-6x+8y+13=0,求x-y/x+y的值.
若整数 x,y 满足x²+4x+y²-6y+13=0,求x , y的值.
若x²+y²﹣4x﹣10y+29=0求分式x/10y-y/10x的值
4/X+1/Y=2,XY=-1,求代数式4Y-X/X-2Y/(x+2y-12Y²/x-2y)的值
如果2x-y=10,求代数式[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y的值
求[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值,其中2x-y=8.
已知2x-y=10,求代数式[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值?