(1)-3a^2b+6ab (2)(x^2-2x)^2+2(x^2-2x)+1 (3)(m+n)(m-n)-(1-2n)
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(1)-3a^2b+6ab (2)(x^2-2x)^2+2(x^2-2x)+1 (3)(m+n)(m-n)-(1-2n)
(1)-3a²b+6ab
=-3ab(a-2b)
(2)(x²-2x)²+2(x²-2x)+1
=[(x²-2x)+1]²
=[(x-1)²]²
=(x-1)
(3)(m+n)(m-n)-(1-2n)
=m²-n²-1+2n
=m²-(n²-2n+1)
=m²-(n-1)²
=(m+n-1)(m-n+1)
再问: (2)(x²-2x)²+2(x²-2x)+1 =[(x²-2x)+1]² =[(x-1)²]² =(x-1)⁴ ↑正确的
=-3ab(a-2b)
(2)(x²-2x)²+2(x²-2x)+1
=[(x²-2x)+1]²
=[(x-1)²]²
=(x-1)
(3)(m+n)(m-n)-(1-2n)
=m²-n²-1+2n
=m²-(n²-2n+1)
=m²-(n-1)²
=(m+n-1)(m-n+1)
再问: (2)(x²-2x)²+2(x²-2x)+1 =[(x²-2x)+1]² =[(x-1)²]² =(x-1)⁴ ↑正确的
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