计算9^[(log3(-2)^2]= 怎么算
log3(2)*log8(9)怎么计算?
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
log 243÷log9 =log3^5÷log3^2 =log3^5-log3^2 然后怎么写
解不等式(2+log3 x)log3 x>log3 (9x)
log2(3)+log3(5)+log3(2)=?
一道对数计算,log3(27/5)+log3(2/3)-log3(6/5)
log3(2)*log8(9)
Log3(9^2*27^(1/3))=?
log3(5)/log3(10)怎么算的?
log2(3)=a,log3(7)=b.log12(56)=log3(7*8)=log3(7)+3log3(2)
2log3底2-log3底32/9+log3底8
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)