[(x+2y)²-(x-y)(3x-y)-5y²]÷(2x)要过程,谢谢
化简:1.2x²-y²+(2y²-3x²)-(2y²+x²)
(x+y)²-2(x²-y²)+(y-x)²
已知2x-y=10 【(x²+y²)-(x-y)²+2y(x-y)】÷4y 过程
(3x-2y)²(3x-2y)²(9x²+4y²)²
求一道计算题,{(2\3x²)-(2\x²+y²)*[(x²+y²\3
已知(x+2)²+|x+y+5|=0,求3x²y+{-2x²y-[-2xy+(x²
化简再求值[(x²+y²)²-4x²y²]÷(x²-y&su
[(x+2y)²-(x+y)(3x-y)-5y²]÷(2x),其中x,y满足x²+4x+y
「(x²+y²)-(x-y)²+2y(x-y)」÷4y,其中2x-y=18
2x-y=10 【(x²+y²)-(x-y)²+2y(x-y)】÷4y
(x+y)^5+2(-x—y)^3·(x+y)²;
再求代数式(4x²-7x+6y-1)-(-2x²+3y²+2y+2x)+(-6x²