lim n→∞(3n2+cn+1/an2+bn-4n)=5,求常数a、b、c的值
已知lim[(3n^2+cn+1)/(an^2+bn)-4n]=5,求常数a、b、c的值
已知lim((an2+5n-2)/(3n+1) -n)=b 求a b的值
lim (n→∞) [(an^2+bn+c)/(2n+5)]=3,求a,b
lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5
a,b为常数.lim(n->无穷)an^2+bn+2/2n-1=3 求a,b
已知lim n→无穷 (an^2+bn+5)/(3n-2)=2,求a,b的值
数列{an}的前n项和sn=an2 +bn(a,b为常数),试证明{an}是等差数列,并求a1和d.
等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn
已知数列an,bn,cn满足[a(n+1)-an][b(n+1)-bn]=cn
求数列极限lim=[(an^2+bn-1)/(4n^2-5n+1)]=1/b 求a b的值
数列{an}的前n项和为Sn,存在常数A,B,C,使得an+Sn=An2+Bn+C对任意正整数n都成立.若数列{an}为
数列极限的题目已知lim(n趋向无穷大)(5n-根号(an^2-bn+c))=2,求a,b的值