t趋于0时为什么lim(sint+cost-1)/t=lim(cost-sint)=1)
t属于(0,π),sint+cost=1/3,求cos2t
a∫1/sint*dt-a∫sint*dt =a*ln|tan(t/2)|+a*cost+C
∫cost/(sint^2) dt =∫dsint/sint^2 =-1/sint + C
求极限,t趋于0 lim t/根号下1-cost 等于多少?
已知﹛x=7(t-sint),y=7(1-cost),则dy/dx=
设x=t^2+cost,y=1-sint,求dy/dx
一道积分题求助(t-sint)√(1-cost) dt
参数方程x=cost+sint,y=sint*cost*(t为参数)的普通方程是多少
x(t)=t-sint y(t)=1-cost,想建立x与y的方程,
设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2 sint-tcost/4t^3 和 sint-tc
(t-sint)(1-cost)√(1-cost)对t从0到2π积分,请问应该怎么积~
∫dt/(1+sint+cost)