不等式tan(2x-π4
解不等式tan(2x+π/3)>(根号3)/3
1)tan(x/2+π/4)+tan(x/2-π/4)=2tanx
tan(X/2+π/4)+tan(x/2-π/4)=2tanx?
求证:tan(x/2+π/4)+tan(x/2-π/4)=2tanx
tan( x/2+π/4)+tan(x/2-π/4 )=2tanx
tan(x/2+ π4)+tan(x/2- π/4)=2tanx
∫ ( tan^2 x + tan^4 x )dx
求不定积分∫(tan^2x+tan^4x)dx
证明sec x+tanx=tan(π/4 +x/2)
2tan^2(x/2)+2=4tan(
求使不等式成立的X值1) 1+tan x>=02) tan x-根号3>=03) sin x>=(根号3)/2 (x属於
解不等式:tan(3x-π/3)小于等于 -(根号3)