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log9^3+log2^1/25×log3^1/8×5^1/9=

来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/11/06 01:51:58
log9^3+log2^1/25×log3^1/8×5^1/9=
原式
= lg3/lg9+lg(1/25)/lg2×lg(1/8)/lg3×lg(1/9)/lg5
= lg3/(2lg3)+(-2lg5)/lg2×(-3lg2)/lg3×(-2lg3)/lg5
= 0.5-12
= -11.5
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7) 计算（log4 3+ log8 3）（log3 2+ log9 2）-- log1/2 32^(1/3)+5^（log2 (log2(3)+log8(9))x(log3(4)+log9(8)+log3(2)) (log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程 log3 5-log3 15+1/2log9 27 的值 [log2(3)+log4(9)][log3(4)+log9(2)]等于 (log4＾3+log8＾3)(log3＾2+log9＾2)+log2＾(32)的1/4次方 （log2 3+log4 27）*（log3 4+log9 8）= 1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 (log2^3 +log3^5) x ( log3^5 +log9^5 ) x lg 2 , 计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15 log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?