question 3

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/07/09 10:26:24

解题思路：证明三角形全等可得结论
解题过程：
解：
OD＝OC，PC＝PD，
证明：
∵MD⊥OB，MC⊥OA，∴∠ODM＝∠OCM＝90°
又∠DOM＝∠COM，OM＝OM
∴△DOM≌△COM，∴OD＝OC，
又∠DOP＝∠COP，OP＝OP
∴△DOP≌△COP，∴PD＝PC。
最终答案：略

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