(1)、(-2m+n)²·(-2m-n)²
化简m/(m+n)²+n/m²-n²-2n²/(m+n)(m²-n
【(m+n)(m-n)-(m-n²)+2n(m-n)】÷4n
(m+n)²+2(m+n)+1因式分解,
(m²-2m)²n+2n(m²-2m)+n
设m等于1/5n求 2n/(m+2n)+m/(2n-m)+4mn/(4n²-m²)
化简-3(m-n)²-(m-n)平方-3(m-n)+4m-n)的平方+2(m-n)-1
(m+n)(m-n)-(1-2n)化简
(1)(m²-3m)²n+2n(m²-2m)+n
因式分解:(m-n)²-(2n-m)²
分解因式 2n(m+n)²+2m(m+n)²+(m+n)³
(m-n)的5次方÷(n-m)的2次方×(m-n)÷(m-n)²计算
(2m-n)²-(m+2n)(m-2n) 因式分解