main () {int a=1,b=2,m=0,n=0,k;k=(n=b>a)||(m=a
main () {int a=1,b=2,m=0,n=0,k;k=(n=b>a)||(m=a
#include int main( ) { int a ,b,m ,n ; m = n = 1 ; scanf( "%
#includeint a(int x);int b(int y);int main(){int m,n;n=6;m=a
#include int main() { int n,a,sum=1,k; scanf("%d",&n); for(k
a,b,k为大于2的正整数a^k mod (k+1)=n;b^k mod (k+1)=m; 证明 n*m mod (k+
int b=2;int fun(int*k) {b=*k=b;return (b);} main() {int a[10
#include main() { int a=1,b=2,c=3,d=4,m=5,n=6; a=(m=a>b)&&(n
#include #define M 20; void main() { int i,j,k,p,t,n=0; int
define M 5#define N M+M main(){int k;k=N*N*5; printf("%d",k)
main( ) {int k=4,a=3,b=2,c=1;printf ("%d\n",k<a
#include "stdio.h" main() { int m,n; float k; for (m=6;m>2;m
#include main() {int a,b,k=4,m=6,*p=&k,*q=&m; a=p==&m; b=(--