{m/5-n/2=2 2m+3n=4},
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
如果m和n互为相反数,则m+2m+3m+4m+5m+5n+4n+3n+2n+n=
如果m,n互为相反数,求m+2m+3m+4m+5m+5n+4n+3n+2n+n=多少
已知2m+n分之m-2n=3,则2m+n分之3(m-2n)+3(2m+n)分之m-2n-4(2m+n)分之5(m-2n)
3m+4n-[2m+(5m-2n)-3n]其中m=n分之一=2
若5m-3n=-4,求出2(m-n)+4(2m-n)
已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=?
m-{n-2m+[3m-(6m+3n)+5n]}=
已知m-2n/2m+n=5,求代数式3(m-2n)/2m+n-15(2m+n)/m-2n-2
若2m-n/m+2n=5,求3(2m-n)/m+2n-m+2n/2m-n+3的值
诺2m-n/m+2n=5,求3(2m-n)/m+2n-m+2n/2m-n+3的值
已知m=5 4/7,n=4 3/7, 求代数式[-7/2(m+n)]^3×(m-n)×[-2(m+n)(m-n)]^2的