5x-4y+2z=8 2x+7y-3z=19 3x+2y-z=18
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x/2=y/3=z/5 x+3y-z/x-3y+z
2x+3y-z=11 2x+y-5z=8 -2+7y+z=19
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?
已知2x+5y+4z=6 3x+y-7z=-4求x+y-z
5x+3y+2z=2011 4x+6y+7z=2012 求x+y+z
已知x+4y+3z=3x-2y-5z=0,求x+2y-z/2x-3y+7z的值
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?