Y=2X-7 5X+3Y+2Z=2 3X-4Z=4 解是多少
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
解方程:{2x+3y+z=7,x+y+z=4,3x+y-z=-4
2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
解方程组:x+y+z=4,x+y+2z=5,3x+y-z=6
已知2x+5y+4z=6 3x+y-7z=-4求x+y-z
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?
5x+3y+2z=2011 4x+6y+7z=2012 求x+y+z
已知方程组4x-y+3z=0 2x+y+6z=0且xyz不等于0,则x/y+y/z+z/x是多少
解方程一;{x+y-z=6,x-3y+2z=1,3x+2y-z=-7.②{3x+4z=7,2x+3y+z=9,5x-9y
已知x+4y+3z=3x-2y-5z=0,求x+2y-z/2x-3y+7z的值
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
{5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-