2x+3y+2z=10 3x+4y+z=11 4x+5y+z=12
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
x/2=y/3=z/5 x+3y-z/x-3y+z
解下列方程组(1)3x-y+z=3 2x+y-3z=11 x+y+z=12(2)5x-4y+4z=13 2x+7y-3z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
若4x-3y-6z=0,x+2y-7z=0,求代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10
1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6
x+2y+3z=10,x-y+4z=10,x+3y+2z=2
x+2y+4z=17 2x+y+z=7 3x+y+2z=11
x-y+4z=10,x+3y+2z=2,x+2y+3z=11.