y=x^3+2x^2+1,dy/dx=?
dy/dx-2y/(1+x)=(x+1)^3
(x^2)dy+(y^2)dx=dx-dy
dy/dx-y/x=x^2
2*x*y^2(dy/dx)- x^3(dy/dx)=2y^3
dy/dx,y=(1+x+x^2)e^x
dy/dx=2y/x+3x/2y
从(dx)/(dy)=1/y '导出:(d^2x)/(dy^2)=-y''/(y')^3
x^2+xy+y^3=1,求dy/dx
微分方程 dy/dx=(-2x)/y
试从dx/dy=1/y'导出:d^2x/dy^2=-y''/(y')^3 题目中关于d[1/y']/dx}*[dx/dy
dy/dx-2y/(x+1)=(x+1)^2
微分方程 dy/dx=(e^y+3x)/x^2