(1+1/1997+1/1999+1/2001)×(1/1997+1/1999+1/2001+1/2003)-(1+1/
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/08/31 07:33:38
(1+1/1997+1/1999+1/2001)×(1/1997+1/1999+1/2001+1/2003)-(1+1/1997+1/1999+1/2001+1/2003)×(1/1997+1/1999+1/2001)=[1+(1/1997+1/1999+1/2001)]×(1/1997+1/1999+1/2001+1/2003)-[1+(1/1997+1/1999+1/2001+1/2003)]×(1/1997+1/1999+1/2001)=1/1997+1/1999+1/2001+1/2003-1/1997-/1999-1/2001=1/2003
设1/1997+1/1999+1/2001=A
原式=(1+A)×(A+1/2003)-(1+A+1/2003)×A
=(A+1/2003)+A×(A+1/2003)-A-(A+1/2003)×A
=1/2003
原式=(1+A)×(A+1/2003)-(1+A+1/2003)×A
=(A+1/2003)+A×(A+1/2003)-A-(A+1/2003)×A
=1/2003
(1+1/1997+1/1999+1/2001)×(1/1997+1/1999+1/2001+1/2003)-(1+1/
简便计算:1997+1998+1999+1998*1997= 和2001除2001又2001/2003+1/2003
一列数1 2001 2000 1 1999 1998 1 1997 1996.第2001个数是什么
2001-1999+1997-1995+1993-1991+.+5-3+1=
1999*1998/1+1999*2000/1+2000*2001/1+2001*2002/1+2002*2003/1+
2004+2003-2002-2001+2000+1999-1998-1997+...8+7-6-5+4+3-2-1
2004+2003-2002-2001+2000+1999-1998-1997+.+8+7-6-5+4+3-2-1
2004+2003+2002-2001-2000+1999+1998-1997-1996+...+4+3-2-1
2003-2002+2001-2000+1999-1998+1997-1996+1995-1994+.+3-2+1=?
2004 +2003-2002-2001+2000+1999-1998-1997+.+4+3-2-1
1999÷1999/1999/2000+1/2001
1999/1999又1999/2000+1/2001