先化简 在求值(a 1分之2 a²分之a 2)÷a 1分之a,其中a=(-1)
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1.2x-1+x+2=3x+12.化简得(a^2+ab)/(a^2-b^2)代入数字得6/73.分母有理化得A/(X-5)+B/(X+2)=(5X-4)/(X^2-3X-10)[A(X+2)+B(X-
(1)-2(a²+1)+3(a+5)-2分之1(4a²-2a)=-2a²-2+3a+15-2a²+a=-4a²+4a+13当a=1/2时,原式=-4*
=[(a²-4)/(a-2)]×1/a(a+2)=[(a+2)(a-2)/(a-2)]×1/a(a+2)=(a+2)×1/a(a+2)=1/a
a是方程x^2+3x-6的根则有a^2+3a-6=0a^2+3a=6(a^2-4a+4分之a^2-4—2-a分之1)÷a^2-2a分之2=((a+2)(a-2)/(a-2)^2+1/(a-2))*(a
a=1/(2+√3)=2-√3原式=(a+1)(a-1)/(a-1)-√(a-1)²/[a(a-1)]=a+1+(a-1)/[a(a-1)]=a+1+1/a=2-√3+1+1/(2-√3)=
原式=(a-1)/(a+2)×(a+2)(a-2)/(a-1)²×(a+1)(a-1)=(a-2)(a+1)=a²-a-2∵a²-a=0∴原式=0-2=-2
(a-1)/(a+2)*(a^2-4)/(a^2-2a+1)÷1/(a^2-1)=(a-1)/(a+2)*(a+2)(a-2)/(a-1)^2*(a+1)(a-1)=(a+1)(a-2)=a^2-a-
[(a-2)/(a+3)]/[(a^2-4)/(2*a-6)]-[5/(a+2)]化简后等于-3/(a+2),这样就行了吧,可以带入值了
=6a平方+5a平方-10ab+5a-12a平方-10ab-3a=-a平方-20ab+2a=-2
a的平方-4分之4+2-3分之1=a的平方-4分之4+3分之5=[(2012-4)(2012+4)]分之4+3分之5=1012032分之1+3分之5=1012032分之1686721再问:真的?能分开
(a-根号3)乘(a+根号3)-a(a-6)=a^2-(√3^2)-a^2+6a=6a-3当a=√5+1/2时,原式=6*(√5+1/2)=3+6√5
问题表述不清再问:a²+2a+1a-----------------------其中a=√3+1a²-1a-1再答:3分之根号3再问:要过程再答:呵呵
(a+2a+1)/(a-1)-a/(a-1)=(a+1)^2/(a+1)(a-1)-a/(a-1)=(a+1)/(a-1)-a/(a-1)=1/(a-1)由a=根号3+1,所以原式=1/(a-1)=1
a/(a-b)-a^2/(a^2-2ab+b^2)÷[(a/a+b-a^2/(a^2-b^2)]+1=a(a-b)/(a-b)^2-a^2/(a-b)^2÷[a(a-b)/(a^2-b)-a^2/(a
原式=(a²-6a+8)-(a²-4a+3)=a²-6a+8-a²+4a-3=-2a+5=-2×(-5/2)+5=5+5=10
请放心使用有问题的话请追问再问:(2)5/3a^2nb3分之5a(a的2n次方)b再答:满意请及时采纳哦,谢谢
原式=(2aa−1-aa−1)÷a=aa−1×1a=1a−1,当a=2+1时,原式=12+1−1=12=22.
a²-1/a-1×根号(a²-2a+1)/a²-a,=(a+1)*|a-1|/[a(a-1)]a>1时=1+1/aa1所以原式=1+1/a=(1+3*根号3)/(1+2*