先化简再求值[x分之x 2减去x-2分之x-1]÷
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题目有误吧(x-x)x-1分之4(x-x)+(x-2)再问:(x方-x)(x-2)方再答:
x的平方-1/x的平方-2x+1除以x+2/x-1减去1/x+2=(x-1)(x+1)/(x-1)²÷(x+2)/(x-1)-1/(x+2)=(x+1)/(x-1)*(x-1)/(x+2)-
解:原式=(x-y)×(xy)分之(xy)的平方-(x-y)的平方乘以(x的平方×y的平方)分之(y的平方-x的平方)=-(xy分之4)当x=2根号3,y=2-根号3时;代入-(xy分之4),结果为5
(x-1/x)/((x²-2x+1)/x)=((x²-1)/x)/((x-1)²/x)=(x+1)(x-1)/(x-1)²=(x+1)/(x-1)=6/4=3/
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小括号内先通分:分母为x平方-4,分子为3x平方+6x,另一个是x平方-2x化简:{x²-4分之2x²+8x}÷x²-4分之2x结果=x+4
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x²+2x+1=10(x+1)²=10x+1=3或x+1=-3所以x=2或x=-4【(x²+4)/x-4】÷【(x²-4)/(x²+2x)】=【(x&
答案是不是二分之X+2的平方—X的平方之一最后是5+2倍的根下2
原式=(x-1)(x+1)/(x+2)*(x+2)/x-1=x+1然后代入数值即可很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,
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