关于"分式"的计算题和代入求值题-搜答案-智慧作业帮

计算题：[1/(m²-m)]+[(m-5)/(2m²-2)]={1/[m(m-1)]}+{(m-5)/[2(m+1)(m-1)]}通分,最简公分母是2m(m+1)(m-1)={2(

.-9(x-2)-y(x-5)当x=5,y=12时,求式子的值.2.5(9+a)×b-5(5+b)×a当a=5/7时,求式子的值.3.62g+62(g+b)-b当g=5/7,b=16时,求式子的值.4

给你说下思路分母分别转化一下形式x^2+3x+2=(x+1)(x+2)x^2+4x+3=(x+1)(x+3)x^2+5x+6=(x+2)(x+3)所以,把它们都转化为分母是(x+1)(x+2)(x+3

先把前二项相加通分后等于2/（1-X^2）,再加上第三项,得出4/（1-X^4）,再加上最后一项,得出8/（1-X^8)

第一题,最后多了一个a,6b^3第二题对的再问：第（3）和（4）能帮忙算下吗(๑•̀ㅂ•́)و✧再答：3

原式=（3-1）/(1*2*3)+(4-2）/(2*3*4)+...+(100-98)/(98*99*100)=1/2-1/6+1/6-1/12+1/12...1/(98*99)-1/(99*100)

1、=X2/(x-1)-(x-1)(x-1)/(x-1)=X2/(x-1)-(X2-2x+1)/(x-1)=(2x-1)/(x-1)再问：一。x+1怎么变成(x-1)(x-1)/(x-1)的

(1)m/(m²-1)·(m²+m)/m²；(2)(x-2)/(3-x)·(x²-6x+9)/(x²-4)；(3)(3x-6)/(x²-4)

解原式=(x-y)/(x+y)+(x-y)(x+y)/(x+y)²-2=(x-y)/(x+y)+(x-y)/(x+y)-2=(x-y+x-y)/(x+y)-2=(2x-2y)/(x+y)-2

原式=9x²-4-5x²+5x-4x²+4x-1=9x-5=-3-5=-8

(a-1)分之(a的平方-a)-1=(a-1)分之a(a-1)-1=a-1

1/[a(a+1)]+1/[(a+1)(a+2)+1/[(a+2)(a+3)]+……+1/[（a+2004)(a+2005)] =1/a-1/(a+1)+1/(a+1

1/ab=(1*c)/(ab*c)=c/abc【分子、分母同时扩大相同的倍数,分数的大小不变.】

[x²y²/(x²-y²)]³×[(y²-x²)/x³y²]²=x^6y^6/(x²-y&

1,原式=(-2+x+2)/(2-x)=x/(2-x)2,原式=〔(x+2)²-(x-2)²〕/(x+2)(x-2)=8*x/(x²-4)3,原式=〔a²-4+

3x+27=06x-5=0x-4x-1=0t(t+3)=282x+3=7xx(3x+2)=6(3x+2)(3–t)+t=9x2=645x2-=0（x+5）2=168（3-x）2–72=02y=3y22

解原式=√2-1+2√2-1/2-3√2+1=(√2+2√2-3√2)+(-1-1/2+1)=-1/2[(x-1)-8/(x+1)]÷[(x²+2x-3)/(1-x²)]=[(x&

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-60/(x-1)(x-2)(x+2)(x+3).第一项和第四项结合,第二三项结合,分子都一直是常数.还是挺好算的……

有28页都是计算题