化简6倍x加y的三次方乘以x减y的二次方的差的二次方-搜答案-智慧作业帮

实数y=根号下x减2加根号下2减x有意义∴﹛x-2≥02-x≥0∴x=2此时y=0x²×y³=0

x^2+2x+y^2-6y+10=0可以化解为（x+1)^2+(y-3)^2=0,等价于x+1=0且y-3=0,所以有x=-1,y=3,故x^3*y=-3.

x+y=7x^2+y^2=55(x+y)^2=x^2+y^2+2xy=492xy=49-55=-6,xy=-3（x^3）·（y^3）=(xy）^3=(-3)^3=-27

3a-1=5;2b+1=3,你懂了吗?

X³+Y³=(X+Y)(X²-XY+Y²)

x^3y-2x^2y^2+xy^3=x^3y+2x^2y^2+xy^3-4x^2y^2=xy(x^2+2xy+y^2)-4x^2y^2=xy(x+y)^2-4x^2y^2=12×7×7-4×12×12

x×x×x－3×x×x＝0x×x²－3×x²＝0x×x²＝3×x²x×x²÷x²＝3×x²÷x²x＝3

3x^2-x=19x^4+12x^3-2x^2-7x+2005=3x^2×(3x^2-x)+5x×(3x^2-x)+(3x^2-x)-6x+2005=3x^2+5x+1-6x+2005=3x^2-x+

x^3+3x^2-3x-9=0x^2(x+3)-3(x+3)=0(x+√3)(x-√3)(x+3)=0所以x=-√3或x=√3或x=-3

(x-y）³×（x-y）²×（y-x）=（x-y）³×（x-y）²×[-(x-y)]=-（x-y）的6次方

先分解因式,后乘法.(X^4-Y^4)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X+Y)(X^2+Y^2)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X^3+X^2Y+XY^2+

（y-x)的五次方

∵x

1、-(X-Y)的8次方2、-（A-B-C)的6次方都是偶次方是不是可以化为正呢?!

7x^3-6x^3y+3x^2y+3x^3+6x^3y-3x^2y-10x^3,其中x=-2010.y=2012=(7x^3+3x^3-10x^3)+(6x^3y-6x^3y)+(3x^2y-3x^2

你可以看了,心形的

x³-y³-x²y+xy²=(x³-y³)-(x²y-xy²)=(x-y)(x²+xy+y²)-xy

-(x-y)^10那位错了吧如果有什么不懂的,欢迎继续问我来自“理科最强”团队

原式=（x+y)^3(x-y)-(x+y)(x-y)^3=(x+y)(x-y)[(x+y)^2-(x-y)^2]=(x+y)(x-y)[x^2+2xy+y^2-x^2+2xy-y^2]=4xy(x+y