化简根号2x-2y除以x除以根号x-y除以2x平方y-搜答案-智慧作业帮

因为x=1+根号2y=1减根号2所以xy=1+根号2乘以1减根号2=1-2=-1x+y=2所以可以求得,原式=xy/(x+y)=-1/2

8√(x³y)/√(2x)＝4x√(2y)；

1.根号下5减2倍根号6=根号(（根号3-根号2）^2)=根号3-根号22.√xy/(y√x-x√y)=√xy/(√xy^2-√x^2y)=√xy/(√xy(√y-√x))=1/(√y-√x)=(√y

(x-y+x+y)/(x^2-y^2)*((x-y)^2/2x)=2x/(x-y)(x+y)*((x-y)^2/2x)=(x-y)/(x+y)x=根号3,y=负根号2原式=（根号3+根号2）/（根号3

解题思路：本题主要考查了，二次根式的除法，根据法则即可计算。解题过程：

.（x-4根号xy+4y）除以（根号x-2根号y）+（2根号xy+x）乘以根号x分之一=(根号x-2根号Y)^2/(根号X-2根号Y)+(2根号XY+X)*根号X/X=根号X-2根号Y+(2X根号Y+

根号32x除以根号2xy乘以2根号y的三次方=(4√2x)÷(√2xy)×(2√y³)=4÷(√y)×(2y√y)=8y

原式=1÷2×√[xy/(y²/x)]=1/2×√(x²y/y²)=x√y/(2y)

【(x-y)^2+(x+y)(x-y)】除以2x=(x-y)*(x-y+x+y)/2x=(x-y)*2x/2x=x-y

∴y=[√(4-x^2)+√(x^2-4)-1]/(x+2).4-x^2≥0,x^2≤4,－2≤x≤2；x^2-4≥0,x^2≥4,x≤-2,或x≥2,∴x=2,y=(0+0-1)/(2+2)=-1/

两个根号相乘就是根号内的式子相乘他们的积开根号（2x-2y）/x*y/2x^2(x-y)的开根号（你说的2x的平方的意思是2x^2吧,如果是4x^2的话自己再算一算吧）x>y>0,所以x-y>0根式都

根号则x-3≥0x≥3分母³√(x-1)-2≠0³√(x-1)≠2x-1≠8x≠9定义域是[3,9)∪(9,+∞)

可能题有误.若x^2+y^2-4x-2y+5=0.(x-2)^2+(y-1)^2=0x=2,y=1根号x+y除以根号下x-y为根3

题目是这样的不：y

x+2y=33根号(x-2y)/根号(4x^2-16y^2)=3/[2根号(x+2y)]=3/(2根号3)=(根号3)/2

=(√x+√y)²/(√x+√y)=√x+√y

可知x≥0,y≥0(x-y)/(√x+√y)-(x-2√xy+y)/(√x-√y)=(√x+√y)(√x-√y)/(√x+√y)-(√x-√y)²/(√x-√y)=(√x-√y)-(√x-√

(x-y)/(√x-√y)=(√X+√y)(√x-√y)/(√x-√y)=√x+√y

根号2x乘以根号y分之x乘以（根号x分之y除以根号y分之一）=根号2x^2/y*（根号y/x*根号y）=根号2x^2/y*根号y^2/x=根号2x/y再代入x、y的值就可以了.

[(x²-y²)²/(x+y)²]/(x-y)=[(x+y)(x-y)/(x+y)]²/(x-y)=(x-y)²/(x-y)=x-y如果不懂