2x-1分之x-1=1-2x分之2-3x
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(1)y=x/x(x-1)*(x-1)²/(x-1)(x+1)-2/(x+1)=1/(x+1)-2/(x+1)=-1/(x+1)=1/3∴x+1=-3,x=-4即x=-4时,y=1/3(2)
答:1)x/(x^2-x)+2=2x/(x+1)1/(x-1)=2x/(x+1)-2=-2/(x+1)-2x+2=x+13x=1x=1/3经检验,x=1/3是原分式方程的解2)x/(x+1)-1=3/
x=0可以先提一个X出来得到x(1/X-1-1/x-2)=0当x=0或x-1=x-2时成立显然后者不成立所以x=0
1、x+3分之2x=(x²+3x)分之2x²;2、(x+y)²分之x²-y²=(x+y)分之x-y再问:把下列各式约分:1、1-m²分之m&
一、(6x+1)/(x^2-x+3)(4x-3)/(-x^2+x-3)=(3-4x)/(x^2-x+3)二、3x/[(x-1)(x-2)]=3x/(x^2-3x+2)(3+x)/[(x-1)(2-x)
原式得:1/(x-3)=2-x/(x-3)两边同时乘以x-3得:2x-6-x=1x-6=1x=7
原式=[(1-1分之x+5)-(1-1分之x+4))+(1-1分之x+3)-(1-1分之x+2)]*[(x+3)(x+5)]\(x^2+7x+13)=[(1分之x+2)-(1分之x+3)+(1分之x+
[(x+2)+1]/(x+2)-[(x+1)+1]/(x+1)=[(x+4)+1]/(x+4)-[(x+3)+1]/(x+3)1+1/(x+2)-1-1/(x+1)=1+1/(x+4)-1-1/(x+
1x-2x(x-2)=---+--------÷--------x(3x-1)^23x-111=---+------÷xx3x-13x-11=--------+-------x(3x-1)x(3x-1
(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)=(x²-x-6+x-3)/x(x-3)=
1、x-x-1分之1=1X(X-1)=X-1(X-1)^2=0X=1,经检验X=1是增根,原方程无解.2、1-x分之1-2=1-x²分之3x-x²(1+X)-2(1-X^2)=3X
左右都有X^2,故把它们都约去,剩下X分之6=X+1两边都乘以x得6=x平方+x移项x平方+x-6=0因式分解(x-3)(x+2)=0解得x=3或x=-2
数学之美团为你解答1/(1-x)+1/(1+x)+2/(1+x²)+4/(1+x⁴)+8/(1+x^8)+16/(1+x^16)+32/(1+x^32)=2/(1-x²
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再问:再答:
(x+1)/(x+2)-1/(x+7)=(x+2)/(x+3)-1/(X+6)(X+2-1)/(X+2)-1/(X+7)=(X+3-1)/(X+3)-1/(X+6)1-1/(X+2)-1/(X+7)=
裂项相消:1/[x(x+1)]+1/[(x+1)(x+2)]+1/[(x+2)(x+3)]+...+1/[(x+2011)(x+2012)]=1/x-1/(x+1)+1/(x+1)-1/(x+2)+1
2x/(x+1)+1/x=2(2x^2+x+1)/x(x+1)=22x^2+x+1=2x(x+1)2x^2+x+1=2x^2+2xx=1
X²-X/X²-2X+1-X/X+1=X(X-1)/(x-1)²-X/X+1=X/X-1-X/X+1=2/2-1-2/2+1=2-2/3=4/3