3x²﹢4xy-y²

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利用x-y=3^2009,xy=-3^2010,求代数式:(2x+3y-2xy)-(x+4y+xy)-(3xy+2y-2

﹙1﹚原式=2x+3y-2xy-x-4y-xy-3xy-2y+2x=3x-3y-6xy=3﹙x-y﹚-6xy=3×2^2009-6×3^2010=3^2010-6×2^2010=﹣5×3^2010.﹙

先化简,再求值 ⒈2(Xy+Xy)-3(Xy-xy)-4Xy,其中X=1,y=-1

1.2(Xy+Xy)-3(Xy-xy)-4Xy=2*2xy-0-4xy=4xy-4xy=02.1/2ab-5aC-(3acb)+(3aC-4aC)=1/2ab-5ac-3acb-ac=1/2ab-6a

求方程组的解,方程组xy/(2x+y)-xy/(2x-y)=3,xy/(2x-y)+xy/(2x+y)=4

xy/(2x+y)-xy/(2x-y)=3xy/(2x-y)+xy/(2x+y)=4;一、两公式对加得2xy/(2x+y)=7xy=(2x+y)*7/2二、把xy代入原公式求解就行了:(2x+y)*7

x^+2xy+y^+4=16 x^-2xy+y^=16 求(3xy+6y^)+|x^-(2xy+2y^-3x^)|的值

x^+2xy+y^+4=16(x+y)²=16-4=12(1)x^-2xy+y^=16(x-y)²=16(2)(1)-(2)2y*2x=-4xy=-1(3xy+6y^)+|x^-(

已知x-y=4xy,求x-2xy-y分之2x+3xy-2y的值!

因为x-y=4xy所以x-2xy-y=2xy2x+3xy-2y=11xyx-2xy-y分之2x+3xy-2y=5.5

(-3x^y+2xy)-( )=4x^+xy

(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^

已知:x-y=1,xy=-2.求:(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值

(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-6xy+3x-3y=-6×(-2)+3×1=15

已知xy≠0,且x²-3xy-4y²=0,则x比y的值为多少?

解题思路:将原方程右边分解因式为(x-4y)(x+y)=0,可得x=4y或x=-y,进而可求出x与y的比值。解题过程:解:∵x2-3xy-4y2=0∴(x-4y)(x+y)=0∴x=4y或x=-y∵x

x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2

x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2=16x^3y^3-49x^3y^3-45^3y^3=-78x^3y^3如果本题有什么不明白可以追问,

(2x²y-3xy²)-3(x²y-2xy²)+2(x²y-4xy&#

(2x²y-3xy²)-3(x²y-2xy²)+2(x²y-4xy²)=2x²y-3xy²-3x²y+6xy&

xy=-2,x+y=3,求代数式(4xy+12y)+[7x-(3xy+4y-x)]

(4xy+12y)+[7x-(3xy+4y-x)]=4xy+12y+7x-3xy-4y+x=xy+8x+8y=xy+8(x+y)=(-2)+8*3=-2+24=22

若x-y=4,xy=1,求(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值

(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-2xy+2x+3y-3xy-2y+2x-x-4y-xy=-6xy+3x-3y=-6xy+3*(x-y)当时,原式=-6*1+3*

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

3x²-4xy+y²

(3x-y)(x-y)(a+b-3)(a-b+1)(3x+2y)(2x-y)(xy+1)(3xy-5)(2a-b+c)(2a-b-c)改了题了:4a²-4ab+b²-c²

3x²y+xy²-[2xy²-4x²y+(x²y-2xy²)

原式=3x²y+xy²-2xy²+4x²y-x²y+2xy²=3x²y+4²y-x²y+xy²-2x

5xy^2-[3xy^2-(4xy^2-2x^y)]+x^2y-xy^2如何化简

5xy^2-[3xy^2-(4xy^2-2x^y)]+x^2y-xy^2=5xy^2-3xy^2+(4xy^2-2x^y)+x^2y-xy^2=5xy^2-3xy^2+4xy^2-2x^y+x^2y-

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-x)^29^-x*27^y=3^-2x*3^3y=3^(-2x+3y)=3^(-

.已知:x-y=1,xy=-2.求:(-2xy+2 x+3y)-(3xy+2y-2x)-(x+4y+xy)的值

(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-2xy+2x+3y-3xy-2y+2x-x-4y-xy=-6xy+3x-3y=-6*(-2)+3*1=15不懂可追问,有帮助请采