3x的平方-7x 4=0
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x²-13x+1=0两边除以xx+1/x=13两边平方可得x²+1/x²+2=169x²+1/x²=167两边平方可得x^4+1/x^4=167&su
x^2-3x+1=0x^2+1=3x两边同除以xx+1/x=3x^2+1/x^2=(x+1/x)^2-2=9-2=7x^4+1/x^4=(x^2+1/x^2)^2-2=49-2=47
x的平方-13x+1=0x+1/x=13(0)(0)两边平方x^2+2+1/x^2=169x^2+1/x^2=167(1)(1)两边再平方x^4+2+1/x^4=27889则x^4+1/x^4=278
x^2-3x+1=0x^2+1=3x同时除以xx+1/x=3所以x^2+1/x^2=(x+1/x)^2-2=3^2-2=7x^2/(x^4+x^2+1)=1/(x^2+1+1/x^2)=1/8
x²+5x+1=0x+5+1/x=0∴x+1/x=-5x²+1/x²=(x+1/x)²-2=25-2=23(x²+1/x²)²=x
x²-3x+1=0两边同除以x得x-3+1/x=0即x+1/x=3x平方/x4次方+x平方+1这里分母是x4次方,则x平方/x4次方+x平方+1=1/x²+x²+1=﹙x
x²+1=-3x两边平方x^4+2x²+1=9x²x^4+1=7x²两边平方x^8+2x^4+1=49x^4x^8+1=47x^4两边除以x^4x^4+1/x^
分析:降次x^2=5x-1所以(x^4+1)/x^2=[(5x-1)^2+1]/(5x-1)=(25x^2-10x+2)/(5x-1)=[25(5x-1)-10x+2]/(5x-1)=(115x-23
x²-3x+1=0同除以xx+1/x-3=0x+1/x=3两边平方x²+1/x²+2=9x²+1/x²=7x²/(x^4+3x²+
x2(2表示平方)-5x+1=0两边除以xx-5+1/x=0x+1/x=5两边平方x²+2+1/x²=25x²+1/x²=23两边平方x^4+2+1/x^4=5
应该是x+x分之1=3吧原式=(x平方+1+x平方分之1)分之1=[(x+1/x)平方-1]分之1=(3平方-1)分之1=8分之1
X的平方-5x+1=011x-5-——=0x-——=5xx(x^4+1)分之x的平方先算它的倒数:x^4+111————=x^2+———=(x-——)^2-2把上面化简了的代入:(5)^2-2=25-
x^2-3x+1=0x^2+1=3xx+1/x=3(x+1/x)^2=9x^2+1/x^2+2=9x^2+1/x^2=7(x^2+1/x^2)^2=49x^4+1/x^4+2=49x^4+1/x^4=
X^2-3X+1=0x+1/x=3x^2+1/x^2+2=9x^2+1/x^2=7x^4+1/x^4+2=49x^4+1/x^4=47
x²-3x+1=0可以得出x≠0两边同除以x得x-3+1/x=0即x+1/x=3x²+1/x²=(x+1/x)²-2=7x⁴+1/x⁴=
x⁴+2x³+4x²+3x+2=x⁴+x³+x²+x³+x²+x+2x²+2x+2=x²(x
(x4+x2+1)/x2=x2+1+1/x2=(x+1/x)^2-2+1=9-1=8所以所求=1/8(x4=x^4,凑合看)
6X^2-7xy-3y^2-x+7y-2=6x^2-(7y+1)x-(3y^2-7y+2)=6x^2-(7y+1)x-(y-2)(3y-1)=[2x-(3y-1)][3x+(y-2)]=(2x-3y+
x平方-3x+1=0二边同除以xx-3+1/x=0x+1/x=3x^2+1/x^2=(x+1/x)^2-2=3^2-2=7x^4+1/x^4=(x^2+1/x^2)^2-2=7^2-2=47
x^2-4x+1=0两边除以xx+/x=4则x^2+1/x^2=14x^4+1/x^4+2=14^2则x^4+1/x^4=14^2-2