作业帮因式分解1-12x^2y^2 48x^4y^4
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/08 23:33:17
(x+1)(y+1)
4(x+y)^2-20(x+y-1)+5=4(x+y)^2-20(x+y)+20+5=4(x+y)^2-20(x+y)+25=[2(x+y)]^2-2*[2(x+y)]*5+5^2=[2(x+y)-5
(x-y)^2-(x-y)^3=(x-y)^2[1-(x-y)]=(x-y)^2(1-x+y)2.（x+y）^2-（x+y）^3=（x+y)^2[1-(x+y)]=(x+y)^2(1-x-y)3、（x
9(x+y)^2-6(x+y)+1=【3(x+y)-1】²
是(2x-y)²-4x+2y+1原式=(2x-y)²-2(2x-y)+1=(2x-y-1)²
（x-1)²-2y(x-1)+y²=x²-2x+1-2xy+2y+y²=x²-2xy+y²-2x+2y+1=(x-y)²-2(x-
4（x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(y^2-4y+4)-2x(2-y)=(y-2)^2+2x(y-2)=(y-2)(2x+y-2)
x^2(x^2-y^2)-12y^4=x^4-x^2y^2-12y^4=(x^2-4y^2)(x^2+3y^2)您好,很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,
1:(x^2-9y^2)-(x+3y)=（x+3y）（x-3y）-(x+3y)=(x+3y)(x-3y-1)提取公因式2：(a-b)^4-(b-a)^2=(a-b)^4-(a-b)^2=(a-b)^2
1-x-y+xy=(1-x)-(y-xy)=(1-x)-y(1-x)=(1-x)(1-y)
=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)
xy-x-y+1=x(y-1)-y+1=x(y-1)-(y-1)=(y-1)(x-1)
原式=（3x+3y-1）（3x+3y+1）标准的十字相乘法.
(x+y)的平方+2(x+y)+1=(x+y)²+2×(x+y)×1+1²=(x+y+1）²
好像不能分解!看看原题?再问：原题是比较x^2+y^2+1与x+y+xy的大小。。。再答：x、y的关系或取值条件没有给出？用作差法比较x^2+y^2+1-(x+y+xy)=x^2-2xy+y^2+xy
25(x-y)^2-1=﹝5(x-y)+1﹞﹝5(x-y)-1﹞
(x-1)(y-1)
这个不能分解的,题目错了
xy-x-y+1=x(y-1)-(y-1)=(x-1)(y-1)(xy-x-y+1)^2=(x-1)^2(y-1)^2
(x-2y)^2-12(x-y)+36=(x-2y)^2-12(x-2y+y)+36=(x-2y)^2-12(x-2y)-12y+36=(x-2y-6)^2-12y=(x-2y-6)^2-(2√3y)