如图 角1= 角2 =角3 ,AB=AD.求正:BC=DE
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ab+a=-2,ab+b=-10两等式相减,得:a-b=8-2a-{-4b-3[(ab+a)²-a]}-1/2[(ab+b)²-2b]=-2a-{-4b-3[(-2)²-
(2-ab+2a+5b)-(3ab+2b-2a)-(3a+4b-ab)=2-ab+2a+5b-3ab-2b+2a-3a-4b+ab=a-b-4ab+2=4-4+2=2
(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)=-2ab+2a+3b-3ab-2b+2a-a-4b-ab=-6ab+3a-3b=-6ab+3(a-b)=6
(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)=-2ab+2a+3b-3ab-2b+2a-a-4b-ab=-6ab+3a-3b=-6ab+3(a-b)=-6*1+3*4=-6+1
(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)=-2ab+2a+3b-3ab-2b+2a-a-4b-ab=(-2ab-3ab-ab)+(2a+2a-a)+(3b-2b-4b)=-
再答:不懂欢迎追问再答:满意麻烦采纳一下谢谢
(a-1)²+|b+1|=0a-1=0、b+1=0解得:a=1、b=-13ab-2(a²-ab)-(a²-ab)=3ab-3(a²-ab)=3ab-3a
a^2-3ab+b^2/ab=(a^2+b^2)/ab-3
(3a-4b-ab)-(a-2b+3ab)=3a-4b-ab-a+2b-3ab=2a-2b-4ab=2(a-b)-4ab=2×(-1)-4×(-2)(将a-b=-1,ab=-2代入)=-2+8=6
a^2-3ab+b^2/ab=(a^2+b^2)/ab-3
可以确定再答:因为a+b=A,ab=A+2011,则1-2(a+ab)+(ab-2b)=1-2a-2ab+ab-2b=1-ab-2(a+b)=1-A-2011-2A=3A,所以A=-335,所以a+b
''^''表示几次方的意思,如3的3次方=3^3一、[2ab(ab+2)-(ab+1)2+(ab+1)(ab-1)+2]÷(-ab)=(2a^2b^2+4ab-a^2b^2-2ab-1+a^2b^2-
把a+b=1,ab=-2代入(-2ab+10a+3b)-3(ab-a-2b)+2(a+3b+ab)=(-2*-2+10a+3b)-3*(-2-a-2b)+2(a+3b-2)=4+10a+3b+3a+2
由1-2(a+ab)+(ab-2b)=3A1-2a-2ab+ab-2b=3A1-2(a+b)-ab=3A1-2A-(A+2008)=3A1-2A-A-2008=3A6A=-2007A=-334.5a+
2a^2b+ab^2-3a^b+5ab-2ab^2-3ab=-a^2b-ab^2+2ab=-ab(a+b)+2ab=-10×1+2×10=10
最后等于4,关键就在于-a-b那里要添括号变成-(a+b)就好
(2a-3b-ab)-(a-2b+3ab)=2a-3b-ab-a+2b-3ab=a-b-4ab=-1-4×(-2)=7
1-2(a+ab)+(ab-2b)=1-2(a+b)-ab=1-2A-A-2008=3A,A=-669/2,所以a+b=-669/2,ab=-3347/2☆⌒_⌒☆诚心为您解答每一个问题!您的好评是我
原式=-2ab+10a+3b-3ab+3a+6b+2a+6b+2ab=15a+15b-3ab=15(a+b)-3ab=15×1-3×(-2)=21
原式=2a+3b-2ab-a-4b-ab-3ab-2b+2a=3a-3b-6ab=3(a-b)-6ab=3*3-6*1=3