如图5,C分线段AB的比为5:7,点D分线段AB的比为5:11,已知CD=10
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设AB=X则AC=2X/3AD=X/4所以CD=AC-AD=5X/12=10X=24cm
由题意可知:AC=(5/8)AB,AD=(3/8)ABCD=AC-AD=(1/4)ABAB=4CD=40cm
MA=5/12ABNA=5/16ABMN=MA-NA=5/48AB=10所以AB=96
AC=AB/2AD=3/5*ABCD=AD-AC=AB*3/5-AB/2=AB(6/10-5/10)=AB*1/10AB=CD*10=70cm再问:很好,没有更好的就选你了再答:谢谢,得到你的肯定
DA:DB=3:2AC=CB所以DC=(1/10)*AB所以AB=80cm
AC:CB=5:3AD:DB=3:5AC=5/8*ABDB=5/8*ABAC+DB=5/8*AB+5/8*ABAB+CD=5/4*ABCD=1/4*ABAB=4*CD=4*10=40(CM)
由题意可知:AC=(5/8)AB,AD=(3/8)ABCD=AC-AD=(1/4)ABAB=4CD=40cm
∵C点分线段AB为3比5D分线段AB为3比7∴AC:BC=3:5AD:BD=3:7又∵AB=40∴AC=15BD=40*7/10=28∴DC=BD+AC-AB=15+28-40=3
设AB的长为xcm,根据题意得:512x-516x=2,解得x=19.2.∴AB的长为19.2cm.
设AD=3X,DB=2X,则AB=5XAC=AB/2=5X/2CD=AD-AC=3X-5X/2=X/2=8cm可得X=16cm所以AB=5X=5*16=80cm
CD=AC-AD=1/3AB-1/4AB=1/12AB=2AB=24再问:用方程怎么算啊再答:设AB长度为a则AC=1/3a,AD=1/4aCD=1/3a-1/4a=21/12a=2a=24一样的,学
AC=5/12AB,AD=5/16AB,CD=2,CD=(5/12-5/16)AB=2,AB=2/(5/48)=19.6
AM=5/(5+7)*AB=5AB/12AN=5/(5+11)*AB=5AB/16MN=AM-AN=5AB/12-5AB/16=(5*4AB-5*3AB)/48=5AB/48=10AB/48=2AB=
∵AC;BC=5:7∴AC=AB×5/(5+7)=5/12AB∵AD:BD=5:11∴AD=AB×5/(5+11)=5/16AB∴CD=AC-AD=5/12AB-5/16AB=5/48AB∵CD=15
/>∵AC:BC=5:7∴AC=5/(5+7)×AB=5/12AB∵AD:BD=5:11∴AD=5/(5+11)×AB=5/16AB∴CD=AC-AD=5/12AB-5/16AB=(20-15)/48
设AD=aDC=b=10CB=cAB=dd=a+10+c(a+10)/c=5/7a/(10+c)=5/11a=30b=10c=56AB=d=a+b+c=30+10+56=96
点C分线段AB5:7∴AC=5/12AB点D分线段AB为5:11∴AD=5/16AB∵CD=AC-AD=5㎝∴5/12AB-5/16AB=5㎝AB=48㎝
AC=5/12ABAD=5/16ABCD=AC-AD =(5/12-5/16)AB =5/48AB =5则,5/48
A——D—C——B∵AC:BC=5:7∴AC=5/(5+7)×AB=5/12AB∵AD:BD=5:11∴AD=5/(5+11)×AB=5/16AB∴CD=AC-AD=5/12AB-5/16AB=(20