6x的三次方y的二次方 2x的平方y=
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A-B=x³+2y³-xy²-(-y³+x³+2xy²)=x³+2y³-xy²+y³-x³
6x的四次方+7x的三次方y+5x的二次方y的二次方-xy的三次方-2y的四次方=6x^4+7x³y+5x²y²-xy³-2y^4=6x^4+7x³y
x^2=y+4,所以x^2-y=4y^2=x+4,所以y^2-x=4x^3-2xy+y^3=(x^3-xy)+(y^3-xy)=x(x^2-y)+y(y^-x)=4x+4yx^2=y+4,y^2=x+
原式=(8x^6-6x^6-12x^5)÷(-2x²)=(2x^6-12x^5)÷(-2x²)=-x^4+6x³再问:=(2x^6-12x^5)÷(-2x²)=
原式=-3x²y-10x^3+3x^3+6x^3y+3x²y-6x^3y+7x^3=0很明显,代数式的值与x,y无关
=-xy/2*(4x²-4xy+y²)=-xy/2*(2x-y)²
再问:谢谢大神再答:有问题继续密我
x的平方y再答:公因式就是共有的东西再问:在问一下(x+y-z)(x-y+z)-(y+z-x)(z-x-y)的公因式是什么再答:x+y-z再答:把负号放到(z-x-y)里再问:哦
(y-x)的二次方(x-y)+(x-y)的三次方+2(x-y)的二次方(y-x)=(x-y)²(x-y)+(x-y)³-2(x-y)²(x-y)=(x-y)³+
-x^4+x^2y^2=x^2(y^2-x^2)=x^2(y+x)(y-x)xy^3-2x^2y^2+x^3y=xy(y^2-2xy+x^2)=xy(x-y)^2
(x-2y)2*(2y-x)3=(x-2y)2*(2y-x)2*(2y-x)=(x-2y)2*(x-2y)2*-(x-2y)=-(x-2y)5结果等于-(x-2y)的5次方
(4x的三次方y+6x的二次方y的二次方-xy的三次方)÷2xy=xy(4x²+6xy-y²)÷2xy=2x²+3xy-0.5y²
x+y的三次方*x+y的二次方=(x+y)^3(x+y)^2=(x+y)^(3+2)=(x+y)^5
x³y³-2x²y²+xy=xy(x²y²-2xy+1)=xy(xy-1)²
x^3-9x=x(x^2-9)=x(x+3)(x-3)16X^4-1=(4x^2+1)(2x+1)(2x-1)6xy^2-9x^2y-y^3=-y(9x^2-6xy+y^2)=-y(3x-y)^2
x^3+x-y^3-y=(x^3-y^3)+(x-y)=(x-y)(x^2+xy+y^2)+(x-y)=(x-y)(x^2+xy+y^2+1).x^3-x^2-y^3+y^2=(x^3-y^3)-(x
99^2=(100-1)^2=100^2-2*100+1=10000-200+1=90801123^2-122*124=123^2-(123-1)(123+1)=123^2-(123^2-1)=110
x(x-y)^2-2(y-x)^3把(y-x)^3变为-(x-y)^3原式变为:x(x-y)^2+2(x-y)^3提出公因式(x-y)^2原式变为:(x-y)^2[x+2(x-y)]把后面这项展开原式
17x的9次方,上式为2x的9次方-64x的9次方+81x的9次方
结果是3(x-y)的2次方与(2x-5y)的积3(x-y)的2次方乘以2(x-y)-3(x-y)乘以3y,提取3(x-y)的2次方得3(x-y)的2次方乘以(2x-2y-3y),合并得:3(x-y)的