已知2的2n加1次方=16 求[n减2]的2016加n次方的值

程序如下：#include#includevoidmain(){inti,n,sum=0;scanf("%d",&n);for(i=1;i{sum+=pow(i,i);}printf("%d",sum

2^2n+4^n=484^n+4^n=484^n=24n=log4(24)再问：n=log4(24)这不能不能用文字叙述一下下下下再答：以4为底，24的对数再问：对数是啥再答：对数是一种运算，如果你没

n^2+n-1=0n^2+n=1n^2=1-nn^3-2n+2011=n*n^2-2n+2011=n(1-n)-2n+2011=n-n^2-2n+2011=-n^2-n+2011=-(n^2+n)+2

2^(4m+6n)=2^4m*2^6n=4^2m*4^3n=7^2*5^(3/2)=49*√125=245√5更号啊

8^(m+n)=(2^3)^(m+n)=2^(3m+3n)=(2^m)^3*(2^n)^3=a^3*b^32^(m+n)+2^(3m+2n)=2^m*2^n+2^3m*2^2n=ab+a^3*b^2

2的n次方减2的负n次方=6,2^n-2^(-n)=6[2^n-2^(-n)]^2=362^2n-2*2^n*2^(-n)+2^(-2n)=362^2n-2+2^(-2n)=362^2n+2^(-2n

2^4m=(2^2m)²=3²=92^6n=(2²)^3n=4^3n=5所以,原式=(2^4m)*(2^6n)*[2^(-2)]=45/4

5^m=11可得：5^4m=2^4=1625^n=11可得：5^2n=115^(5m-2n+1)=16÷11x5=80/11再问：5m^11哪来的啊再答：打错了5^m=2可得：5^4m=2^4=162

n+1+m+n=10m-2n=1m=5n=2m的n次方=25

2^(n+4)-2^(n+1)=1122^(n+4)-2^(n+1)=2^(n+1)(8-1)=7^2^(n+1)=112=7*16=7*2^47^2^(n+1)=7*2^4所以n+1=4,n=3

2的n+m次方=2的n次方×2的m次方=8×16=144

3的m次方等于6,所以3的2m次方等于369的n次方等于2,所以3的2n次方等于2,3的4n次方等于4原式等于36÷4×3=27再问：为什么乘以3再答：最后要求的指数中还有加1这一项，所以要乘以3

2^(2n+3)-2^(2n+1)=192令a=2^2n则2^(2n+3)=8a2^(2n+1)=2a所以8a-2a=192a=322^2n=32=2^52n=5n=5/2

f(x)=x^4+mx^3+nx-16有因式(x-1),(x-2),则：f(1)=1+m+n-16=0,m+n=15f(2)=16+8m+2n-16=0,8m+2n=0解方程组得：m=-5,n=20

2^(2n+3)-2^(2n+1)=1922^(2n+1)(2^2-1)=1923*2^(2n+1)=1922^(2n+1)=64=2^62n+1=62n=5n=2.5

2^(2n+1)+4^n=482^(2n+1)+2^2n=482^2n(2+1)=482^2n=162n=4n=22^2=4

x^(6n)+x^(4n)*x^(5n)=x^(6n)+x^(9n)=[x^(3n)]^2+[x^(3n)]^3=2^2+2^3=4+8=12

n方减n减1的n加2次方等于1则n²-n-1=1或n+2=0或n²-n-1=-1且n+2为偶数则n=2或-1或-2或0

2的2n+1次方+4的n次方=482的2n+1次方+2的2n次方=482×2的2n次方+2的2n次方=483×2的2n次方=482的2n次=16=2的4次方2n=4n=2再问：为什么是3×2的2n次方