已知x^2 xy 2y=14,y^2 xy 2x=-15,求x y的值

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已知(5X+Y-7)²+/4X-2Y-14/=0,求X、Y的值

(5X+Y-7)²+/4X-2Y-14/=0由非负性5x+y-7=0.(1)4x-2y-14=0.(2)(1)*2+(2)得14x-28=0x=2代入(1)得10+y-7=0y=-3解得x=

已知2/x+2/y=根号24,求 x/y(x-y) - y/x(x-y)的值

2/x+2/y=根号24(2y+2x)/xy=2√6x+y=xy√6x/y(x-y)-y/x(x-y)=1/(x-y)[(x/y-y/x)]=1/(x-y)[(x²-y²)/xy]

已知2/x 2/y=根号24,求 x/y(x-y) - y/x(x-y)的值

你的题目有点问题我这样做了x/{y(x-y)}-y/{x(x-y)}=(x平方-y平方)/{xy(x-y)}=(x+y)/xy2/x+2/y=2(x+y)/xy=根号24

已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s

已知x+y/x=11/8,求x-y/x+2y的值

(x+y)/x=11/88x+8y=11y8x=3yy=8x/3(x-y)/(x+2y)=(x-8x/3)/(x+16x/3)=(-5x/3)/(19x/3)=-5/19

已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²

原式=(2x-y)(x+y)/(2x-y)^2=(x+y)/(2x-y)x/y=2x=2y原式=3y/3y=1

高数:已知f(x+y,y)=x^2+y^2,求f(x,y)

这道题实际就是要把x^2+y^2变换成只由x+y和y组成的多项式x^2+y^2=x^2-y^2+2y^2=(x+y)(x-y)+2y^2=(x+y)[(x+y)-2y]+2y^2将式中(x+y)替换为

数学题已知p=x^/x-y-y^/x-y,q=(x+y)^-2Y(X+Y),

你的题是什么意思?“^/”是什么意思?

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

已知4x-3y=7,3x+2y=19,则14x-2y=?

两式相加4x3+3x-3y+2y=7+97x-y=1614x-2y=16x2=32

已知2x+5y+4z=15.7x+y+3z=14 则x+y+z=?

设a(2x+5y+4z)+b(7x+y+3z)=x+y+z比较系数得2a+7b=5a+b=4a+3b=1a=1/11,b=2/11因此x+y+z=a(2x+5y+4z)+b(7x+y+3z)=1/11

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?

X^2表示平方X^2+4X+4+Y^2-2Y+1=0(X+2)^2+(Y-1)^2=0因为平方大于=0所以X+2=0Y-1=0X=-2Y=1X^2+Y^2=5

已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?

即(x-2y)²=0x-2y=0所以x=2y所以原式=(2x²+2xy-xy-y²)/(4x²-4xy+y²)=(2x²+xy-y²

已知 x²-xy+2y²=14,且x-y=6,求x-2y

x²-xy+2y²=14(x-y)x+2y²=146x+2y²=146(y+6)+2y²=142y²+6y+22=0y²+3y+1

已知4x=9y求(1)x+y/y (2)y-x/2x

4x=9yx=9/4*y(1)(x+y)/y=[(9/4)y+y]/y=(9/4+1)y/y=9/4+1=13/4(2)(y-x)/2x=[y-(9/4)y]/[2*(9/4)y]=(1-9/4)y/

已知x,y满足约束条件:x-y+1>=0,x+y-2>=0,x

最小值0.5,1.5,-1最大值1,1,-1/3约束区域是一个三角形,把三角形的三个顶点代入.可以检验出最大值最小值.

已知x+y/y=11/8,求x-y/x+2y的值.

x+y/y=11/8说明11y=8(x+y)即8x=3y所以x-y/x+2y=3(x-y)/3(x+2y)=(3x-3y)/(3x+6y)=(3x-8x)/(3x+16x)=-5/19

已知集合A ={y \y =2~x ,x

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