已知圆X² Y²-10X-10Y=0,X² Y² 6X-2Y-40=0
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(1)C1:x2+y2+2x+2y-8=0与C2:x2+y2-2x+10y-24=0,C1-C2得:4x-8y+16=0,即x-2y+4=0,代入C1得:x(A)=-4,y(A)=0,x(B)=0,y
当x>0,y>0时,方程组整理得:2x+y=10x=12,解得:x=12,y=-14,不合题意;当x>0,y<0时,方程组整理得:2x+y=10x−2y=12,解得:x=6.4,y=-2.8;当x<0
X+y=10,XY=24,则X=4,Y=6或X=6,Y=4,所以(X-Y)(X-Y)=2*2=4或(-2)*(-2)=4,都为4
先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s
x-y-3绝对值+(2x+2y+10)的平方=0X-Y-3=0X-Y=32X+2Y+10=0X+Y=-5(x+y)(x-Y)=3X(-5)=-15
|x|+x+y=10|y|+x-y=12两式相加得|x|+|y|+2x=22.(1)两式相减得|x|-|y|+2y=-2.(2)所以-|y|+2y<0若y>0,则显然-y+2y<0,即y<0,矛盾若y
在坐标系中先作2x+5y≥10对应的直线2x+5y=10,取直线上方区域;然后作2x-3y≥-6对应的直线2x-3y=-6,把y的系数变为正,可知取直线下方区域;最后作2x+y≤10对应的直线2x+y
x²-2x+y²+6y+10=0x²-2x+1+y²+6y+9=0(x-1)²+(y+3)²=0x-1=0y+3=0∴x=1y=-3∴x+y
x^2+2x+y^2-6y+10=0(x+1)²+(y-3)²=0∴x=-1,y=3(x+y)²=(-1+3)²=4
已知2x-y=10,式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y=[x^2+y^2-x^2+2xy-y^2+2xy-2y^2]/4y=[4xy-2y^2]/4y=2y(2x-y)/
x^2+y^2-6x-2y+10=0x^2-6x+9+y^2-2y+1=0(x-3)^2+(y-1)^2=0x=3,y=1(x+y)/(x-y)=4/2=2
x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0x=1y=-3(x-y)/(x+y)=4/(-2)=-2
(1)x^2+y^2-4x+10y+29=0x^2-4x+4+y^2+10y+25=0(x-2)^2+(y+5)^2=0x=2y=-5剩下的自己解下面两个题目是不是写错了,没看懂
(x+y)²=x²+2xy+y²(x-y)²=x²-2xy+y²两式相加得(x+y)²+(x-y)²=2(x²
步骤如下:x^2y^2-8xy+16=-(x^2+y^2-2xy)(xy-4)^2=-(x-y)^2所以得出等式左右都为0!计算得出x=2,y=2
x^2+y^2-10x-12y+61=0(x²-10x+25)+(y²-12y+36)=0(x-5)²+(y-6)²=0因为(x-5)²与(y-6)&
m²+n²=0则有m=0n=0运用这个道理x²+y²-6x+10y+34=0x²-6x+y²+10y+34=0x²-6x+9才能拼
若x≤0,|x|=-x|x|+x+y=10y=10代入x+|y|-y=12得x=12>0矛盾,∴x>02x+y=10①若y≥0,x+|y|-y=x=12y=10-2x∴yx-2y=12②联立①②解得x
4x^2+y-4x-6y+10=0(2x-1)^2+(y-3)^2=0x=1/2y=3y/x-x/y=6-1/6=35/6