已知圆X² Y²-10X-10Y=0,X² Y² 6X-2Y-40=0-搜答案-智慧作业帮

（1）C1：x2+y2+2x+2y-8=0与C2:x2+y2-2x+10y-24=0,C1-C2得：4x-8y+16=0,即x-2y+4=0,代入C1得：x（A）=-4,y（A）=0,x（B）=0,y

当x＞0，y＞0时，方程组整理得：2x+y＝10x＝12，解得：x=12，y=-14，不合题意；当x＞0，y＜0时，方程组整理得：2x+y＝10x−2y＝12，解得：x=6.4，y=-2.8；当x＜0

X+y=10,XY=24,则X=4,Y=6或X=6,Y=4,所以(X-Y)(X-Y)=2*2=4或（-2）*（-2）=4,都为4

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s

x-y-3绝对值+(2x+2y+10)的平方=0X-Y-3=0X-Y=32X+2Y+10=0X+Y=-5(x+y)(x-Y)=3X(-5）=-15

|x|+x+y=10|y|+x-y=12两式相加得|x|+|y|+2x=22.(1)两式相减得|x|-|y|+2y=-2.(2)所以-|y|+2y＜0若y＞0,则显然-y+2y＜0,即y＜0,矛盾若y

在坐标系中先作2x+5y≥10对应的直线2x+5y=10,取直线上方区域；然后作2x-3y≥-6对应的直线2x-3y=-6,把y的系数变为正,可知取直线下方区域；最后作2x+y≤10对应的直线2x+y

x²-2x+y²+6y+10=0x²-2x+1+y²+6y+9=0(x-1)²+(y+3)²=0x-1=0y+3=0∴x=1y=-3∴x+y

x^2+2x+y^2-6y+10=0（x+1)²+（y-3)²=0∴x=-1,y=3(x+y)²=（-1+3）²=4

已知2x-y=10,式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y=[x^2+y^2-x^2+2xy-y^2+2xy-2y^2]/4y=[4xy-2y^2]/4y=2y(2x-y)/

x^2+y^2-6x-2y+10=0x^2-6x+9+y^2-2y+1=0(x-3)^2+(y-1)^2=0x=3,y=1(x+y)/(x-y)=4/2=2

x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0x=1y=-3(x-y)/(x+y)=4/(-2)=-2

（1）x^2+y^2-4x+10y+29=0x^2-4x+4+y^2+10y+25=0(x-2)^2+(y+5)^2=0x=2y=-5剩下的自己解下面两个题目是不是写错了,没看懂

(x+y)²=x²+2xy+y²(x-y)²=x²-2xy+y²两式相加得(x+y)²+(x-y)²=2(x²

步骤如下:x^2y^2-8xy+16=-(x^2+y^2-2xy)(xy-4)^2=-(x-y)^2所以得出等式左右都为0!计算得出x=2,y=2

x^2+y^2-10x-12y+61=0(x²－10x＋25)＋(y²－12y＋36)=0(x－5)²＋(y－6)²=0因为(x－5)²与(y－6)&

m²+n²=0则有m=0n=0运用这个道理x²+y²-6x+10y+34=0x²-6x+y²+10y+34=0x²-6x+9才能拼

若x≤0,|x|=-x|x|+x+y=10y=10代入x+|y|-y=12得x=12>0矛盾,∴x>02x+y=10①若y≥0,x+|y|-y=x=12y=10-2x∴yx-2y=12②联立①②解得x

4x^2+y-4x-6y+10=0(2x-1)^2+(y-3)^2=0x=1/2y=3y/x-x/y=6-1/6=35/6