把下列各式因式分解x²-(a b-c)²
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12.1)78²-22²=(78+22)*(78-22)=100*56=56002)1000²/(252²-248²)=1000²/【(25
1.原式=[2(x+y)+(x-y)][2(x+y)-(x-y)]=(3x-y)(x+3y)2.原式=9a^2b^4-6ab^2+1=(3ab^2-1)^23.原式=[(m/3)^2+n]^24.原式
9a²-4(b+c)²=(3a+2b+2c)(3a-2b-2c)
(1)-2分之1a²+2b²=-2分之1(a²-4b²)=-2分之1(a+2b)(a-2b)(2)a的3次方b-ab的3次方=ab(a²-b²
4xy²-4x²y-y³=-y(4x-4xy+y²)=-y(2x+y)²
1.x(x-y)^2-y(y-x)^2=(x-y)^2*(x-y)=(x-y)^32.18(a-b)^3-12b(b-a)^2=(a-b)^2*(18a-18b-12b)=6(a-b)^2*(3a-5
1.用平方差公式:(z²-x²-y²)²-4x²y²=[(z²-x²-y²)-2xy][(z²-x&
解题思路:解答此题的关键是要掌握分析题中的各种信息条件,寻找题中的数量关系解题过程:解:
(1).1.(x+18)^2=(22+18)^2=16002.(2a-b)^2=(2*1/2-5/4)^2=1/16(2).(2x-3)^2=0x=3/2(3).xy(a-b)^2=5*6^2=180
(2m+3n)(2m-n)-4n(2m-n)=(2m-n)(2m+3n-4n)=(2m-n)(2m-n)=(2m-n)^2(x+y)^2(x-y)+(x+y)(y-x)^2=(x+y)(x-y)(x+
1.ab(a-b)-a(b-a)²=ab(a-b)-a(a-b)²=a(a-b)[b-(a-b)]=a(a-b)(2b-a)2.4(2x+3y)²-(3x-y)²
1、9a²-4b²=(3a)²-(2b)²=(3a+2b)(3a-2b)2、4x²-25y²=(2x)²-(5y)²=(
解题思路:因式分解解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.ph
1、x²-x-1=x²-x+(1/2)²-5/4=(x-1/2)²-(√5/2)²=(x-1/2+√5/2)(x-1/2-√5/2)2、2a²
(1)(a²+1)(a+1)(a-1)(2)(3x-2)(3x-4)(3)(x+2)(x-2)(1-2x)(4)x(2y-3z)²(z+y)(z-y)
一解:(1)原式=(x-1)(7x-7+4)=(x-1)(7x-3)(2)原式=(a-b)(x-y)(3)原式=(p-3)(6m-4n)(4)原式=(y+2)(1-20y-40)=(y+2)(-20y
1.x²+7x+10=(x+2)(x+5)2.x²-3xy-10y²=(x-5y)(x+2y)3.16x⁴-y⁴=(4x²+y²
(1)x^3+3x^2+3x+9=x^2(x+3)+3(x+3)=(x^2+3)(x+3)(2)2x^2+xy-y^2-4x+5y-6=(2x-y)(x+y)-4x+5y-6=(2x-y)(x+y)+
30-11x-30x^2=-(30x²+11x-30)=-(5x+6)(6x-5)2(3x+1)^2-3(3x+1)(y-2)+(y-2)^2=[2(3x+1)-(y-2)][(3x+1)-
4a^2b^3-6ab^2c+8ac=2a(2ab^3-3b^2c+4c)-1/6*x^3-0.5x^2+x=-1/6x(x^2+3x-6)