c 编程输出200~500之间素数,要求每行输出5个-搜答案-智慧作业帮

自己加：#include/*1、输出1-20*/intmain(intargc,char**argv){\x09intmax=20;\x09inti;\x09for(i=1;i0;i--)\x09\x

#include"stdio.h"voidmain(){inti;for(i=1;i

#include <stdio.h>int diffabs(int a,int b) { // 返回a,b差值的绝对值

你的程序中判断素数并加和的部分有问题在你的基础上修改如下PS:main不需要改动# include <stdio.h>int SumPrime(int&nbs

#include#defineN4main(){inti,j,a[N][N]={{3,5,6,3},{0,8,9,1},{0,0,5,0},{0,0,0,7}};for(i=0;ifor(j=0;ji

#include#includeintss(intn)/*检查n是否为素数,如果是则返回1,否则返回0*/{inti;for(i=2;i

#include<stdio.h>int main(){int i,j;for(i=0;i<6;i++){for(j=1;j<6-i;j++)

#include <stdio.h>#include <math.h>int prime (int n){int

longfunc(intm){inti,sum=1;for(i=1;i

#includevoidmain(){inti,sum=0;for(i=100;i{if(i%5==0&&i%7==0){sum+=i;}}printf("\nsum=%d

privatesubform_click()dimnaslongdimxasstringdimyasstringfori=1000to9999x=mid(i,1,2)y=mid(i,4,1)&mid(

#includeintmain(){inta,b,c;intmin,max;scanf("%d%d%d",&a,&b,&c);if(amax)max=c;printf("%d%d%d",max,a+b

/楼主还是多多看看课本、#include <stdio.h>int main(){int sum = 0;int i;fo

#include"stdio.h"voidmain(){inti;for(i=200;i

intmain(intargc,char**argv){inti,j=0;for(i=100;i

直角三角形#include#defineN10intmain(){inti,j;for(i=1;i再问：if(j

①publicclasstest{publicstaticvoidmain(Stringargs[]){intsum=0;for(inti=1;i

#includevoidmain(){intk,sum=0;for(k=1;k

#defineN5#include<stdio.h>voidmain(){ inta[N][N]; inti,j; for

#includevoidmain(){inti=1,count=0;for(;i