E=220√3 sin(100πt π 6)

y=sin（e^-x）这是一个复合函数＝cos（e^-x）*（e^-x）‘＝-e^-x*cos（e^-x）

电动势最大值311V角频率314rad/s周期2×Pi/314约等于0.02s初相位Pi/3再问：PI是啥?再答：圆周率派

(1)f(x)=√3(1-cos2x)-1/2sin2x+√3/2cos2x=√3-1/2sin2x-√3/2cos2x=√3-sin(2x+π/3)∴最小正周期T=2π/2=π单调增区间：π/2+2

#include#includeintmain(void){intfun(inti);inti;floatsum=0.0,x;inttemp=1;scanf("%f",&x);sum=x;for(i=

V|t=0=(dx/dt)|t=0=[-2e^(-2t)*sin(3t+π/6)+3e^(-2t)*cos(3t+π/6)]|t=0=（3√3)/2-1=1.58(m/s)再问：那加速度是多少呢，详解

1.y'=e^(2x)+2xe^(2x)=(1+2x)e^(2x)2.y'=[2xcos2x-sin2x]/x^23.y'=3cos(3x+π/3)

开始时t=0,E=220根号2*sin(π/6)=182.8V第一次取得最大值时100πt+π/6=π/2------>t=1/300秒电压最大值Em=220*根号2=311V

x=sin(y/x)+e^2求dy/dxd(x)=d(sin(y/x)+e^2)dx=dsin(y/x)+de^2dx=cos(y/x)d(y/x)dx=cos(y/x)(xdy-ydx)/x^2x^

我看错了,太难了,把图片给你.我使用软件matlab计算,显示：Warning: Explicit integral could not be&nbs

y=sin(e∧x+1)dy=cos(e^x+1)d(e^x+1)=e^xcos(e^x+1)dx

dy/dx=(e^t×sint)′/(e^t×cost)′=(e^t×sint+cost×e^t)/(e^t×cost-sint×e^t)=(sint+cost)/(cost-sint)当x=π/3=

x+3>0,且ln(x+3)≠0得：x>-3且x≠-2所以,定义域为(-3,-2)U(-2,+∞)

y=6(2x+3)^2y=(e^x^2)2x-2y=cos(π/2x+4)×((-2π/(2x+4)^2))希望我写得清楚

e^xsinxdx=-e^xcosx+[e^xcosxdx=-e^xcosx+e^xsinx-[e^xsinxdx所以2e^xsinxdx=e^xsinx-e^xcosx因此e^xsinxdx=(e^

f(x)=2cos(x-π/6)sin(x+π/6)-√3*(sin(x-π/6))^2+sin(x-π/6)cos(x-π/6）=sin2x+sin(π/3)-(√3/2）[1-cos(2x-π/3

y=e^(x/2)+x^2*sin√xy′=1/2*e^(x/2)+2x*sin√x+x^2*1/（2√x）*cos√x

令x=π/2-t,dx=-dt当x=0,t=π/2,当x=π/2,t=0L=∫(0-->π/2)e^sinx/(e^sinx+e^cosx)dx=∫(π/2-->0)e^sin(π/2-t)/[e^s

sin(x-π/3)-cos(x+π/6)+√3cosx=sinxcosπ/3-cosxsinπ/3-cosxcosπ/6+sinxsinπ/6+√3cosx=1/2*sinx-√3/2*cosx-√

y'=2e^2xcos(e^2x)把y看成复合函数sint,t=e^m,m=2x.复合函数求导,等于三个分别求导的积

sin²α+√3sinαcosα-2cos²α=01-cos²α+√3sinαcosα-2cos²α=01+√3sinαcosα-3cos²α=0√3