genr xt=log(x)
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log(x+5)=log(x)+log(2)log(x+5)=log(2x)x+5=2xx=5log(8)+log(x)=log(24)log(8x)=log(24)8x=24x=32log(x)=l
令t=2+2x-x2=-(x-1)2+3≤3,∵函数y=log13t在(0,+∞)上单调递减∴log13(2+2x-x2)≥log133=-1.故值域为[-1,+∞).故答案为:[-1,+∞)
换底公式y=log7(x+1)=lg(x+1)/lg7=lg1001/lg7计算器或者查表所以原式=3.55
首先,把log(x)(100)变形为1/{log(10^2)(X)}PS:^2是平方的意思把平方提出来为1/1/2{log(10)(X)}=1/[1/2lgX]=2/lgX所以原式=2/lgx-lgx
log(2)[log(3)(log(4)x)]=0log(3)(log(4)x)=1log(4)x=3x=64log(3)[log(4)(log(2)y)]=0log(4)(log(2)y)=1log
由于f(x)=log3mx2+8x+nx2+1的定义域为R,∵x2+1>0,故mx2+8x+n>0恒成立.令y=mx2+8x+nx2+1,由于函数f(x)的值域为[0,2],则1≤y≤9,且(y-m)
log(3x)²=log4(6-x)所以9x²=24-4x9x²+4x-24=0x=(-2±2√55)/9真数3x>0,6-x>0所以x=(-2+2√55)/9再问:lo
loga2
∵log(a)(m/n)=log(a)(m)-log(a)(n)∴-loga1/x=-(loga1-logax)∵log(a)(1)=0∴-(loga1-logax)=logax明教为您解答,如若满意
没有底数吗?还是是lg[(lg(x^2)+lg(x^4))/lg(100x)]=(2lgx+4logx)/lg(100x)=6lgx/(2+lgx)=46lgx=8+4lgx所以.lgx=4x=100
log2x2=22x2=100x2=50x=正负5倍根号2x2指X的平方
比如log(9)a=log(3)a/[log(3)9]=log(3)a/2=log(3)[a^1/2]换底公式而log(2)[16]=log(2)[2^4]=4log(2)2=4
f(x)=log^2(x+1)/(x-1)+log^2(x-1)+log^2(p-x)定义域:(x+1)/(x-1)>0,且x-1>0,且p-x>0x<-1或x>1,且x>1,且x<p∴1<x<pf(
如果数据没错的话应该就是这个答案了.
㏒(X+5)(X+2)=1,X^2+7X+10=10X=0或X=-7,当X=0时,符合题意,当X=-7时,㏒(X+5)无意义,舍去.∴X=0.
log₂log₃log₄X=0log₃log₄X=1log₄X=3X=64log₃log₄logS
log1/7[log3(log2x)]=0=log1/7(1)所以log3(log2x)=1log3(log2x)=log3(3)log2(x)=3x=2³x=8
f(√5)=2log(5)√5=2*1/2=1
2log(b)x=log(a)x+log(c)x2lgx/lgb=lgx/lga+lgx/lgc把lgx约分2/lgb=1/lga+1/lgc=(lga+lgc)/(lgalgc)=lg(ac)/(l