编写程序,计算下面数列前n项中奇数项的和
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PrivateSubCommand1_Click()DimnAsInteger,阶乘项AsLong,阶乘和AsLongDon=Val(InputBox("请输入阶乘的项数(N≤8)"))LoopUnt
PrivateFunctionF(nAsLong)AsLongIfn>2ThenF=F(n-1)+F(n-2)ElseF=1EndIfEndFunctionPrivateSubCommand1_Cli
/>Private Sub Form_Click()'1、* 编写程序,计算并输出下面数列中前n项的和.(设n=20)'  
inta=1;intb=2;intsum=0;for(intn=1;n再问:正确么再答:完整正确的代码如下:#include#include#includevoidmain(){inta=1;intb
#includeintmain(){inti,sum=0;for(i=1;i
main(){inta,sum,i;for(i>0;i
#include"stdio.h"main(){intn,s;n=1;s=0;while(n
PrivateSubCommand1_Click()DimiAsLong,sumAsLongFori=1To50Step2sum=sum+i*(i+1)*(i+2)NextMsgBox"级数前50项奇
#includeusingnamespacestd;#include/*编写程序,计算并输出下面数列前20项的和,结果取3位小数.(C++)2/1,3/2,4/3,5/4,6/5,7/6,8/7,……
#includevoidmain(){inti;doublesum=0;for(i=1;i
sum=sum+1/(5*i+1);这一句,1/(5*i+1)的值是整数的,所以它一直是0这样好像可以sum=sum+(double)1/(5*i+1);
#include"stdio.h"voidmain(){doublea,n,s=0;for(n=1;n
#include"stdafx.h"voidmain(){ints=0;for(intn=1;n
#includevoidmain(){inta1,a2;longintresult=0;inti;for(i=1;i
“i=1”---->"i==1","i=2"------>"i==2"
longn=0;for(inti=1;i
1.dimi,jasIntegerfori=1to20j=j+i*(i+1)*(i+2)nextimsgboxj
#include"stdio.h"voidmain(){floatans=0;inti;for(i=1;i
PrivateSubForm_Click() DimnAsInteger,sAsInteger n=0 s=0
#includeintsum(intn){intj,s=0;for(j=1;j