若方式方程x-4分之x=5+x-4分之a
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x+120=4x/5x-4x/5=-120x/5=-120x=-600
3x+5/4x=1717/4x=17x=17÷17/4x=4
(x+2)分之(x+1)+(x+5)分之(x+4)=(x+3)分之(x+2)+(x+4)分之(x+3)x=-7/2再问:求过程正确答案是负2分之7我知道答案不知道过程再答:1/(2+x)+x/(2+x
1/{(x-1)(x-2)}=1/{(x-4)(x-5)}首先,分母不为零,∴x≠1,2,4,5通分:(x-4)(x-5)=(x-1)(x-2)x^2-9x+20=x^2-3x+26x=18x=3
x+1分之x+2减去x+3分之x+4=x+5分之x+6减去X+7分之x+8方程两边分别通分,得[(x+2)(x+3)-(x+1)(x+4)]/[(x+1)(x+3)]=[(x+6)(x+7)-(x+8
(1-5分之4)x=21+45分之x=25x=25×5x=125
15/20x-1/20x=17.50.7x=17.5x×0.7÷0.7=17.5÷0.7x=25很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,
希望能帮上忙,第一步x-7/x-9+x-3/x-5=x-4/x-6+x-6/x-8第二步(x-9)+2/x-9+(x-5)+2/x-5=(x-6)+2/x-6+(x-8)+2/x-8第三步1+2/x-
你这描述太模糊了,不然早有人回答了再问:已知方程(m的平方-1)x的平方+mx+2=x是关于x的一元一次方程,则m=
解方程(1)x+1分之6=x(X+1)分之x+56x=(x+5)x=1方程左边=3方程右边=(1+5)/1*(1+1)=3所以x=1是方程的解x-4分之3-x+4-x分之1=13-x-1=x-4x=3
原式:5x/(x+9)=x/18x^2+9x=90xx^2-81x=0x(x-81)=0经检验解得x=0或x=81
(x+5)/(x+4)+(x+6)/(x+5)=(x+4)/(x+3)+(x+7)/(x+6)1+1/(x+4)+1+1/(x+5)=1+1/(x+3)+1+1/(x+6)1/(x+4)+1/(x+5
等号前后同时分别计算减法得:(x+1)(x+3)分之2=(x+5)(x+7)分之2所以:(x+1)(x+3)=(x+5)(x+7)x^2+4x+3=x^2+12x+35x=-4
再问:第二个发错了,是X-5分之1X=10分之3再答:再问:脱式计算:2-(5分之1+3分之1)再答:
(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/(x-9)对方程两边各自通分:[(x-4)(x-6)-(x-5)(x-5)]/[(x-5)/(x-6)]=[(x-7
化简3x/5+2x/5-3x/7=4/3x-3x/7=4/34x/7=4/3x=7/3
1+1/(x+2)+1+1/(x+3)=1+1/(x+4)+1+1/(x+1)1/(x+2)+1/(x+3)=1/(x+4)+1/(x+1)1/(x+3)-1/(x+4)=1/(x+1)-1/(x+2
(x+3)/7-(x+2)/5=(x+6)/6-(x+4)/4(1-2x)/35=-2x/2424-48x=-70x22x=-24x=-12/11
1/(X-7)-1/(X-5)=1/(X-6)-1/(X-4)移项1/(X-7)+1/(X-4)=1/(X-6)+1/(X-5)通分(2x-11)/[(x-7)(x-4)]=(2x-11)/[(x-6
X=4原式=(X-1)/(X-2)-(X-2)/(X-3)=(X-4)/(X-5)-(X-5)/(X-6)左边通分=[X^2-4X+3-X^2+4X-4]/[(X-2)(X-3)]=-1/[(X-2)