sin(π 4-x)=(cosx-sinx) √2

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已知函数fx=[cosx+cos(π/2-x)][cosx+sin(π+x)]

f(x_=(cosx+sinx)(cosx-sinx)=cos²x-sin²x=cos2x所以T=2π/2=πf(α/2)=cosα=1/3sin²α+cos²

sin(x+1/2π)=cosx?还是cos-x

cos-x自己画个坐标就一目了然了

已知函数f(x)=2cosx*sin(x+π/3)-√3sin^2x+sinx*cosx

1.f(x)=2cosx*sin(x+π/3)-√3sin^2x+sinx*cosx=2cosx*sin(x+π/3)-2sinx*[(√3/2)sinx-(1/2)cosx]=2cosx*sin(x

已知函数f(x)=2sin(π-x)cosx

∵f(x)=2sin(π-x)cosx=2sinxcosx=sin2x1、最小正周期T=2π/2=π.2、∵-π/6≤x≤π/2∴-π/3≤2x≤π,∴-√3/2≤f(x)≤1,∴最大值1,最小值-√

已知sin(x-3π/4)cos(x-π/4)=-1/4,则cosx等于

sin(x-3π/4)=sin[π-(π/4-x)]=sin(π/4-x)=-sin(x-π/4)sin(x-3π/4)cos(x-π/4)=-sin(x-π/4)cos(x-π/4)=-sin(2x

设f(x)=2cosx.sin(x+π/3)-根号3 sin平方x+sinx.cosx

f(x)=2cosx*sin(x+π/3)-√3sinx^2+sinx*cosx=2cosx*(sinxcosπ/3+cosxsinπ/3))-√3sinx^2+sinx*cosx=sinxcosx+

求证sinx-cosx=根号2sin(x-π/4)

√2sin(x-π/4)=√2(sinxcosπ/4-cosxsinπ/4)=√2[(1/√2)sinx-(1/√2)cosx]=sinx-cosx

已知sinx+cosx/sinx-cosx=2,求2cos(π-x)-3sin(π+x)/4cos(-x)+sin(2π

是(sinx+cosx)/(sinx-cosx)=2和[2cos(π-x)-3sin(π+x)]/[4cos(-x)+sin(2π-x)]吗?如果是的话:(sinx+cosx)/(sinx-cosx)

sinx+cosx=√2sin(x+π/4)

sinx+cosx=√2(cos45°sinx+sin45°cosx)=√2sin(x+45°)==√2sin(x+π/4)

已知sin(kπ+x)=-2cos(kπ+x)求(4sinx-2cosx)÷(5cosx+3sinx),和4sin&su

当K为奇数时,sin(kπ+x)=-2cos(kπ+x)即-sinx=-2(-cosx),于是tanx=-2.当K为偶数时,sin(kπ+x)=-2cos(kπ+x)即sinx=-2(cosx),于是

已知函数f(x)=2cosx*sin(x+π/3)-根号3sin^2x+sinx*cosx

这个简单:f(x)=2cosx(sinxcos(pi/3)+cosxsin(pi/3))-根号33sin^2x+sinx*cosx=2sinxcosx+根号3cos2x=2sin(x+pi/3)所以:

如何得到f(x)=|sinx+cosx|=|根号2sin(x+π/4)|?

f(x)=|sinx+cosx|=|√2(√2/2*sinx+√2/2*cosx|=|√2(sinx*cosπ/4+cosx*sinπ/4)|=|√2sin(x+π/4)|.

利用cosx=sin(π/2-x),sin'x=cosx,证明(cosx)'=-sinx

(cosx)'=[sin(π/2-x)]‘=cos(π/2-x)*(π/2-x)'=sinx*(-1)=-sinx

化简f(x)=4sinx*sin^2((π+2x)/4)+(cosx+sinx)(cosx-sinx)

f(x)=4sinx*sin^2((π+2x)/4)+(cosx+sinx)(cosx-sinx)=4sinx*[1-cos(π/2+x)]/2+cos²x-sin²x=sinx(

已知函数f(x)=1-根号2sin(2x-π/4)/cosx

1).cosx≠0.x≠kπ+π/2.k∈Z.∴f(x)的定义域为{x│x≠kπ+π/2.k∈Z}.2)α是第四象限的角,切tanα=-4/3.sinα=-4/5,cosα=3/5.sin2α=2si

已知函数f(x)={1-(√2)*sin[2x-(π/4)]}/cosx

(1)cosx≠0x≠Kπ+π/2K∈Z(2)由tanα=-4/3可知:sinα=4/5,cosα=-3/5得:sin2α=2sinα*cosα=-24/25cos2α=1-2(sinα)^2=-7/

2sin(x-π/4)sin(x+π/4)=(sinx-cosx)(sinx+cosx)=-cos2a

要用这个公式,你用错了cos(π/2+a)=-sinasina=-cos(π/2+a)2sin(x-π/4)sin(x+π/4)=-2cos[π/2+(x-π&

使f(x)=sinx+cosx=√2*sin(x+π/4) 步骤是什么

和差化积公式.sin(x+y)=sinx*cosy+cosx*siny

怎样使f(x)=sinx+cosx=√2*sin(x+π/4)

f(x)=sinx+cosx=√2(√2/2sinx+√2/2sinxcosx)-------(提一个√2出来)=√2(sinxcosπ/4+cosxsinπ/4)-(把(√2/2分别变为cosπ/4

函数y=sin平方x-cosx,x∈{-π|4,π|4}的值域为

y=(sinx)^2-cosx=1-(cosx)^2-cosx=-(cosx+1/2)^2+5/4x∈(-π/4,π/4)cosx∈(√2/2,1)令cosx=1,得y=-1令cosx=√2/2,得y