使f(x)=sinx+cosx=√2*sin(x+π/4) 步骤是什么
使f(x)=sinx+cosx=√2*sin(x+π/4) 步骤是什么
怎样使f(x)=sinx+cosx=√2*sin(x+π/4)
化简f(x)=4sinx*sin^2((π+2x)/4)+(cosx+sinx)(cosx-sinx)
已知函数f(x)=2cosx*sin(x+π/3)-√3sin^2x+sinx*cosx
sinx+cosx=√2sin(x+π/4)
f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx
已知函数f(x)=[2sin(x+π/3)+sinx]cosx-√3sin²x,x∈R
如何得到f(x)=|sinx+cosx|=|根号2sin(x+π/4)|?
已知函数f(x)=2cosx*sin(x+π/3)-根号3sin^2x+sinx*cosx
设f(x)=2cosx.sin(x+π/3)-根号3 sin平方x+sinx.cosx
已知f(x)=2cosx*sin(x+π/6)+√3sinx*cosx-sin^2x.设三角形ABC的内角A满足f(2)
求函数的单调区间:(1)y=sin(π/4-3x),(2)f(x)=sinx(sinx-cosx)