x根号下xy (y根号下y分之x)
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√xy-√x/y=√5·4-√5/4=2√5-√5/2=3√5/2
根号则x-2>=0,x>=22-x>=0,x
(根号下y-x)平方+根号下x平方-2xy+y平方=√(x-y)^2+√(x-y)^2=2√(x-y)^2=2|x-y|若x≥y,原式=2x-2y若x再问:(根号a+3根号b分之a-9b-3根号a)-
(xy-y²)分之(y×根号x+x×根号y)-(x×根号下x-y×根号下y)分之(x+根号下xy+y)=(y√x+x√y)/(xy-y²)-(x+√xy+y)/(x√x-y√y)=
解题思路:关于解二次根式的计算问题,详细答案请见解析过程解题过程:
-5(根号2)/2
已知x+y=-5,xy=2求√x/y+√y/x√x/y+√y/x=1/y√(xy)+1/x√(xy)=√(xy)(1/y+1/x)=√(xy)[(y+x)/xy]=√2*(-5)/2=(-5√2)/2
[(x×根号x+x×根号y)/(xy-y²)]-[(x+根号下xy+y)/(x×根号x-y×根号y)]=(x√x+x√y)/(xy-y^2)-[x+√(xy)+y]/(x√x-y√y)=[x
题目不很清楚哈,我理解是:已知:x-(xy)^0.5-2y=0;求:(2x-(xy)^0.5)/(y+2*(xy)^0.5);由已知:(x/y)-(x/y)^0.5-2=0;[(X/y)^0.5-2]
x=(根号3-根号2)/(根号3+根号2)=(根号3-根号2)^2/[(根号3)^2-(根号2)^2]=(根号3-根号2)^2=5-2*根号6类似可得y=5+2*根号6xy=1,x^2+y^2=(5-
结果为根号下x+根号下y解2xy/(x根号下y+y根号下x)分母提公因式根号下xy然后前后两式分母都含根号下x+根号下y合并后约分得根号下x+根号下y
是否这样:√[x+y)/xy²]÷√x(x+y)=√[(x+y)/(x+y)x²y²]=√1/x²y²=1/|x||y|再问:是这样麻烦了~再答:知道
∵分子x2-16≥0,16-x2≥0∴x2-16=0x=±4∵分母8-2x≠0x≠4∴x=-4y=(0+0-9)/【8-2*(-4)】=-9/16∴xy=-4*(-9/16)=9/4xy的平方根=±3
x+5√(xy)-6y=0(√x+6√y)(√x-√y)=0√x=-6√y不合题意舍去,√x=√y即x=y……
x-√(xy)-2y=(√x-2√y)(√x+√y)=0因为x>0,y>0所以√x+√y>0所以√x=2√yx=4y2x=8y,√(xy)=2√y*√y=2y原式=(8y-2y)÷(y+4y)=6y/
若x0,则xy√(y/-x)=xy√[-xy/(-x)²]=(xy/-x)√(-xy)=-y√(-xy).
√3xy/√(y/3x)=√3xy/√(3xy/9x)=√3xy/(√3xy)/3x=3x