x的2平方-25分之4y的2平方等于
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若y=根号[(x^2-2)/(5x-4)]+[根号(x^2-2)/(4-5x)]+2[(x^2-2)/(5x-4)]>=0(x^2-2)/(4-5x)]>=0两个相反数同时大于或等于0,两个必须都为0
①-x+2y分之x-y除以x的平方+4xy+4y的平方分之x的平方-y的平方=-(x-y)/(x+2y)÷(x^2-y^2)/(x^2+4xy+4y^2)=-(x-y)/(x+2y)×(x^2+4xy
1-(x-y)/(x+2y)÷(x²-y²)/(x+2y)²=1-(x-y)/(x+2y)×(x+2y)²/(x+y)(x-y)=1-(x+2y)/(x+y)=
x平方+y平方+8x+6y+25=0(x+4)²+(y+3)²=0∴x=-4;y=-3∴(x²-4y²)/(x²+4xy+4y²)-x/(x
3x^2+xy-2y^2=(3x-2y)(x+y)=0x=-2y/3,或x=-y但由于你要求的式子中分母里有X平方-Y平方x=-y舍去其他就代入吧
原式=2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)=(2xy+x²-xy)/(x+y)(x-y)=(x²+xy)/(x+y)(x-y)=x(x+y)/(x+y)
您好:原式=2x/(2x+3y)(2x-3y)-1/(2x+3y)=(2x-2x+3y)/(2x+3y)(2x-3y)=3y/(2x+3y)(2x-3y)如果本题有什么不明白可以追问,如果满意记得采纳
朋友想念你很高兴为您解答!请放心使用,有问题的话请追问采纳后你将获得5财富值.你的采纳将是我继续努力帮助他人的最强动力!再问:答案应该是8y的四次方分之3x的平方y的三次方+x的三次方吧再答:根据题意
(x的平方-y的平方)分之2xy+(x+y)分之x-(y-x)分之y=(x的平方-y的平方)分之2xy+(x+y)分之x+(x-y)分之y=(x²-y²)分之[2xy+x(x-y)
前者分子:x^2-y^2=(x+y)(x-y)那前面这项就可以化简约分啦后者分子:4x^2-4xy+y^2=(2x)^2-2*2xy+y^2=(2x-y)^2建议你理解一下x^2-2xy+y^=(x-
=-(x+2y)(x-2y)/(x+y)²×2x(x+y)/(x-2y)=-2x(x+2y)/(x+y)=-(2x²+4xy)/(x+y)
(x分之x-y)-(y分之x+y)+(2xy分之x的平方-y的平方)=1-y/x-1-x/y+(x^2-y^2)/2xy=-2(y^2+x^2)/2xy+(x^2-y^2)/2xy=-(x^2+3y^
x的平方+2xy+y的平方分之x的平方-4y的评方÷x的平方+xy分之x+2y=(x+2y)(x-2y)/(x+y)²×x(x+y)/(x+2y)=x(x-2y)/(x+y)=(x²
解(x^4-y^4)/(x²-2xy+y²)÷(x²+y²)/(y-x)=(x²-y²)(x²+y²)/(x-y)
原式=[2x/(x-y)]*[y/(x+y)]-[x^4/(x^4-y^4)]/[x^2/(x^2+y^2)]^2=2xy/(x^2-y^2)-(x^2+y^2)^2/[(x^2+y^2)(x^2-y
X的平方+Y的平方-6X-8Y+25=0,整理就是x²+y²-6x-8y+9+16=0即x²-6x+9+y²-8y+16=0于是(x-3)²+(y-4
(1)2xy的平方分之3x的平方y=(2y)分之3x(注:分子分母约掉xy).(2)(x的平方-25)分之(x+5)=[(x-5)(x+5)]分之(x+5)=(x-5)分之1
x的平方-64y的平方分之2x-x-8y分之1=[2x-(x+8y)]/(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)=1/(x+8y)
x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²