(1 x的平方-2x)-(1 x的平方-4x 4)除以2 x的平方-2x-搜答案-智慧作业帮

x(x²-2x+1)-3x(x²-4x+1)=x³-2x²+x-3x³+12x²-3x=-2x³+10x²-2x=-2x

你把题用手机拍一下

=(x-1)(1-x)+x(x-1)²-x(x-1)³+.-x(x-1)²º¹¹+x(x-1)²º¹²

原式=-2x³+6x²-3x³-3x²=-5x³+3x²

=2x/x²-(2x-1)/x²=(2x-2x+1)/x²=1/x²

(3x/x+1-x/x-1)+x-2/x的平方-1=(3x(x-1)-x(x+1))/(x+1)(x-1)+x-2/x^2-1=(3x^2-3x-x^2-x+x-2)/(x^2-1)=(2x^2-3x

1：2分之3X的平方-{-2分之1X平方}+{-2X平方}=3x²/2+x²/2-2x²=4x²/2-2x²=2x²-2x²=02

原式=(x+1)²(x-1)²-4(x+1)²=(x+1)²[(x-1)²-4]=(x+1)²(x-1+2)(x-1-2)=(x+1)&su

(x-6)(x²+x+1)-x(2x+1)(3x-1)=(x³+x²+x-6x²-6x-6)-x(6x²-2x+3x-1)=(x³-5x&#

(x+1)(x-2)-(x-1)²=(x²-x-2)-(x²-2x+1)=x²-x-2-x²+2x-1=x-3再问：呃，可以问一个问题与？再问：吗？抱

原式=[(x+2)/x(x+2)-(x-1)/(x-2)²]÷[(x²-4)/x]×(x-2)²=[x-(x-1)/(x-2)²]×[x/(x+2)(x-2)]

,[x^2-4]/[x^2+x+1]的平方/[x^3-2x^2]/[x^3+x^2+x]的平方*[x/x+2]^3=[(x+2)(x-2)/(x^2+x+1)^2]*[x^2(x^2+x+1)^2/x

x{[1-2/(1-x)]/(x+1)-(x^2-1)/(x^2-2x+1)}=x{[-(x+1)/(1-x)]/(x+1)-(x-1)(x+1)/(x-1)^2}=x{-1/(1-x)-(x+1)/

x+1分之x的平方+2x+1=(x+1)²/(x+1)=x+1

4x²-3x

x^2-2=0x^2=2原式=x^2-2x+1+x^2/x+2=2-2x+1+2/x+2=(2x+4-2x^2-4x+x+2+2)/x+2=(2x+4-4-4x+x+2+2)/(x+2)=4-x/x+

(x-1)(x-2)-2(2-x)^2=(x-1)(x-2)-2(x-2)^2=(x-2){(x-1)-2(x-2)}=(x-2){x-1-2x+4}=(x-2)(-x+3)=-(x-2)(x-3)

9+6+1/9-3+1=13又9分之1

原式=[2x(x+1)/(x+1)(x-1)-x(x-1)/(x-1)²]÷x/(x+1)=[2x/(x-1)-x/(x-1)]×(x+1)/x=x/(x-1)×(x+1)/x=(x+1)/