画出不等式X²+XY-2Y²+X+5Y-2≥0
画出不等式X²+XY-2Y²+X+5Y-2≥0
已知X²-5XY+6Y²=0,求(X²+3XY)\2Y²的值
1-x²+2xy-y²
|x+2y+3|+(2x+y)²=0求x²-xy+y²
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
已知x²-xy-2y²=0,且x、y不等于0,求代数式x²-2xy-5y²除x&
计算:(1).(-2xy²)*(3x²y)²
已知x²-xy-y²=0,且x≠0,y≠0.求代数式(x²-2xy-5y²)/(
已知(x+2)²+|x+y+5|=0,求3x²y+{-2x²y-[-2xy+(x²
已知3x²+xy-2y²=0(x≠0,y≠0),求x/y-y/x-x²+y²/x
已知x/y=3,求x²+2xy-3y²/x²-2xy+y²
x/y=2,求分式x²-xy+3y²/x²+xy+6y²