1+(-2)+3+(-4)+.+2003+(-2004)
来源:学生作业帮 编辑:作业帮 分类:综合作业 时间:2024/10/02 18:58:33
1+(-2)+3+(-4)+.+2003+(-2004)
| 1-1/2 | + | 1/2-1/3 | + | 1/3-1/4 | +.+ | 1/9-1/10 |
| 1-1/2 | + | 1/2-1/3 | + | 1/3-1/4 | +.+ | 1/9-1/10 |
1+(-2)+3+(-4)+.+2003+(-2004)
= (1 - 2) + (3 - 4) + ...+ (2003 - 2004)
= (-1)× 1002
= -1002
| 1-1/2 | + | 1/2-1/3 | + | 1/3-1/4 | +.+ | 1/9-1/10 |
= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ...+ 1/9 - 1/10
= 1 - 1/10
= 9/10
= (1 - 2) + (3 - 4) + ...+ (2003 - 2004)
= (-1)× 1002
= -1002
| 1-1/2 | + | 1/2-1/3 | + | 1/3-1/4 | +.+ | 1/9-1/10 |
= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ...+ 1/9 - 1/10
= 1 - 1/10
= 9/10
1+(-2)+3+(-4)+.+2003+(-2004)
(-1)+(+2)+(-3)+(+4)+...(-2001)+(+2002)+(-2003)+(+2004)
(-1)+(+2)+(-3)+(+4)…(+2001)+(+2002)+(-2003)+(+2004).
(-1)+(+2)+(-3)+(+4)+...(-2001)+(+2002)+(-2003)+(+2004)=?
(1-2)(2-3)(3-4)(4-5)····(2003-2004) 咋算
1+2+(-3)+(-4)+5+6+(-7)+(-8)+…+2001+2002+(-2003)+(-2004)+2005
(1+3+5+.2003+2005)-(2+4+6+.2002+2004)
计算(1+3+5+.+2001+2003+2005)-(2+4+6+.+2000+2002+2004)
(1+3+5+……+2003)-(2+4+6+……+2004)=
(根号3+1)^2004-2(根号3+1)^2003-2(根号3+1)^2002+2004
(1-1/2)(1/3-1)(1-1/4)(1/5-1)……(1/2003-1)(1-1/2004)
用简便方法计算 (1) 2004分之1+2004分之2+2004分之3+…+2004分之2003