若lim[(2n-1)an]=1 求lim(n*an)的值

若lim[(2n-1)an]=1 求lim(n*an)的值 若数列{an}满足a1=根号6 a(n+1)=根号下an+6 (n∈N*) 如果lim an 存在,求lim an的值[ 数列极限的运算lim an/(an+1) =2 求lim 2anlim (2n+1)*an=3 求lim n*an 数列极限（已知lim[（2n-1）an]=2,求lim n*an） lim n趋于无穷 ,an+1/an=q.求lim an=? 已知：lim (n→∞) [(n^2+n)/(n+1)-an-b]=1 ,求a,b的值 lim[(2n-1)an]=2,求limnan lim[(n^2+1)/(n+1)-an-b]=o求a和b的值 lim[1/(a-1)^n]=0 求a的范围 若lim(2n+(an^2-2n+1)/(bn+2))=1 求a/b的值 若数列{an}满足a1=√(6),an+1=√(an+6),(n∈N),如果lim(an)存在,求lim(an) 等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn 已知lim[(an^2+5n-2)/(3n+1)-n]=b,求a,b的值