ln[根号（x^2+y^2）] =arctany/x 求dy

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/11/07 20:56:02

1/2*ln(x^2+y^2)=arctany/x两边对x求导,得
1/2*1/(x^2+y^2)*(2x+2y*y')=1/[1+(y/x)^2]*(y'*x-y)/x^2
化简得
y'=(x+y)/(x-y)
则dy=(x+y)/(x-y)*dx

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