如图,AB=AC,AD=AE,∠1=∠2,试证明BD=CE
如图,AB=AC,AD=AE,∠1=∠2,试证明BD=CE
如图,已知AB=AC,AD=AE,BD=CE,求证:∠3=∠1+∠2
如图,AB=AC,AD=AE,BD=CE.(1)若AD⊥AE,求证:BD⊥CE;(2)若BD⊥CE,求证:∠BAE+∠C
如图,已知AB=AC,AD=AE,BD=CE.试说明:∠BAC=∠DAE
如图,已知AB=AC,AD=AE,试说明:BD=CE.
如图,AB=AC,∠BAC=90°,BD⊥AE于D,CE⊥AE于E 说明1、AD=CE 2、BD=AE
(1)—如图,已知AB=AC,AD=AE,BD=CE.由题设可推出图中哪两个角相等?试给出证明(全部)
已知,如图,AB=AC,AD=AE,BD=CE,AC平分DE.求证:(1)∠BAC=∠DAE;(2)∠BAD=∠CAD.
已知:如图5,AE⊥AB,AD⊥AC,BD=CE,BD⊥CE于O,试说明:AE=AB.
如图,已知,AB=AC,AD=AE,BD=CE.AD⊥AE,求证:(1)BD垂直CE;(2)AB垂直AC;(3)S△AB
已知:如图,AB=AC,AD=AE,BD=CE,求证:∠BAC=∠DAE
如图,AB=AC,AD=AE,BD=CE.求证:∠ADE=∠AED