printf("%d\n",(x=5*6,x*4,x+5));这是什么意思?

printf("%d\n",(x=5*6,x*4,x+5));这是什么意思? void main() {int x=4;if(x++>=5)printf("%d/n",x);else printf( int x=6; x += x -= x * x; printf("x = %d\n",x); #define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf("%d\n",S(k 下列程序段的输出结果是_ int x=3; if(x=5) x++; printf("%d\n",x); 下列程序的输出是( ).main() {int x; printf("%d\n",(x=3*5,x*2,x+10));} main( ) {int x＝5; if (x－－＜5) printf(“％d\n”,x); else printf(“ int x=20; printf("%d\n",x); void main() { int x=0,y=5,z=3; while() printf("%d,%d,%d\n",x 一道C语言简单语法题main(){int x;printf("%d\n",(x=5*6,x*2,x+20));}运行结果 求讲解输出 #include void main() { int x; printf("%d\n",(x=5*8,x*2 main() { int a=5,b=4,x,y; x=a++*a++*a++; printf(“a=%d,x=%d\n